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A) Given the function:

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Answers

2 parts
a

−1x2-\frac{1}{x^2}

b

10x+1x210x + \frac{1}{x^2}

Step-by-step solution

6 steps

Here are the solutions for the differentiation problems:

Part a· 3 steps

Given the function

y=3x+1xy = \frac{3x+1}{x}
  1. Rewrite the function by splitting the fraction.

    y=3xx+1xy = \frac{3x}{x} + \frac{1}{x} y=3+x−1y = 3 + x^{-1}
  2. Differentiate each term with respect to xx.

    Recall that ddx(c)=0\frac{d}{dx}(c) = 0 for a constant cc, and ddx(xn)=nxn−1\frac{d}{dx}(x^n) = nx^{n-1}.

    dydx=ddx(3)+ddx(x−1)\frac{dy}{dx} = \frac{d}{dx}(3) + \frac{d}{dx}(x^{-1}) dydx=0+(−1)x−1−1\frac{dy}{dx} = 0 + (-1)x^{-1-1} dydx=−x−2\frac{dy}{dx} = -x^{-2}
  3. Express the answer with a positive exponent.

    dydx=−1x2\frac{dy}{dx} = -\frac{1}{x^2}

    The derivative is −1x2\boxed{-\frac{1}{x^2}}.

Part b

10x+1x210x + \frac{1}{x^2}

Given the function

y=5x2−1xy = 5x^2 - \frac{1}{x}
  1. Rewrite the second term using a negative exponent.

    y=5x2−x−1y = 5x^2 - x^{-1}
  2. Differentiate each term with respect to xx.

    dydx=ddx(5x2)−ddx(x−1)\frac{dy}{dx} = \frac{d}{dx}(5x^2) - \frac{d}{dx}(x^{-1}) dydx=(2)(5)x2−1−(−1)x−1−1\frac{dy}{dx} = (2)(5)x^{2-1} - (-1)x^{-1-1} dydx=10x−(−1)x−2\frac{dy}{dx} = 10x - (-1)x^{-2} dydx=10x+x−2\frac{dy}{dx} = 10x + x^{-2}
  3. Express the answer with a positive exponent.

    dydx=10x+1x2\frac{dy}{dx} = 10x + \frac{1}{x^2}

    The derivative is 10x+1x2\boxed{10x + \frac{1}{x^2}}.

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