Write the given function.

The function is given as:

$$y = 8x^3 + 15x^2 - 18x + 12$$

For the first term, $8x^3$:

$$\frac{d}{dx}(8x^3) = 8 \cdot 3x^{3-1} = 24x^2$$

For the second term, $15x^2$:

$$\frac{d}{dx}(15x^2) = 15 \cdot 2x^{2-1} = 30x$$

For the third term, $-18x$:

$$\frac{d}{dx}(-18x) = -18 \cdot 1x^{1-1} = -18x^0 = -18$$

For the fourth term, the constant 12:

$$\frac{d}{dx}(12) = 0$$

$$\frac{dy}{dx} = 24x^2 + 30x - 18 + 0$$ $$\frac{dy}{dx} = 24x^2 + 30x - 18$$