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Identify the values for m and n and the binary operation.

Computer Science

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  1. Identify the values for mm and nn and the binary operation.

    The given binary operation is mΔn=1m3−1n3m \Delta n = \frac{1}{m^3} - \frac{1}{n^3}.
    We need to evaluate (3−2)Δ(3+2)(\sqrt{3} - \sqrt{2}) \Delta (\sqrt{3} + \sqrt{2}).
    Let m=3−2m = \sqrt{3} - \sqrt{2} and n=3+2n = \sqrt{3} + \sqrt{2}.

  2. Find the relationship between mm and nn.

    Calculate the product mnmn:

    mn=(3−2)(3+2)mn = (\sqrt{3} - \sqrt{2})(\sqrt{3} + \sqrt{2})

    Using the difference of squares formula (a−b)(a+b)=a2−b2(a-b)(a+b) = a^2 - b^2:

    mn=(3)2−(2)2=3−2=1mn = (\sqrt{3})^2 - (\sqrt{2})^2 = 3 - 2 = 1

    Since mn=1mn = 1, we can write n=1mn = \frac{1}{m}.

  3. Simplify the expression for mΔnm \Delta n using the relationship from Step 2.

    Substitute n=1mn = \frac{1}{m} into the definition of the operation:

    mΔn=1m3−1n3=1m3−1(1/m)3=1m3−11/m3=1m3−m3m \Delta n = \frac{1}{m^3} - \frac{1}{n^3} = \frac{1}{m^3} - \frac{1}{(1/m)^3} = \frac{1}{m^3} - \frac{1}{1/m^3} = \frac{1}{m^3} - m^3
  4. Calculate m3m^3.

    Given m=3−2m = \sqrt{3} - \sqrt{2}.
    First,

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