We read your photo as:

Calculate the missing values for each row in the table using the function y = 2x3 + 5x2 − x − 6.

Computer Science

ScanSolve AI Answer

Graph of y = 2x³ + 5x² − x − 6

Use the left and right arrow keys to trace the curve, up and down to jump between key points, and plus and minus to zoom.

Key points of y = 2x³ + 5x² − x − 6
Pointxy
x-intercept−20
Maximum−1.760.34
x-intercept−1.50
y-intercept0−6
Minimum0.09−6.05
x-intercept10

Step-by-step solution

2 steps
  1. Calculate the missing values for each row in the table using the function y=2x3+5x2−x−6y = 2x^3 + 5x^2 - x - 6.

    For x=−3x = -3:
    y=2(−3)3+5(−3)2−(−3)−6y = 2(-3)^3 + 5(-3)^2 - (-3) - 6
    y=2(−27)+5(9)+3−6y = 2(-27) + 5(9) + 3 - 6
    y=−54+45+3−6=−12y = -54 + 45 + 3 - 6 = -12

    For x=−2x = -2:
    2x3=2(−2)3=2(−8)=−162x^3 = 2(-2)^3 = 2(-8) = -16
    −x=−(−2)=2-x = -(-2) = 2
    y=−16+20+2−6=0y = -16 + 20 + 2 - 6 = 0

    For x=−1x = -1:
    2x3=2(−1)3=2(−1)=−22x^3 = 2(-1)^3 = 2(-1) = -2
    −x=−(−1)=1-x = -(-1) = 1
    y=−2+5+1−6=−2y = -2 + 5 + 1 - 6 = -2

    For x=0x = 0:
    y=2(0)3+5(0)2−(0)−6y = 2(0)^3 + 5(0)^2 - (0) - 6
    y=0+0−0−6=−6y = 0 + 0 - 0 - 6 = -6

    For x=1x = 1:
    y=2(1)3+5(1)2−(1)−6y = 2(1)^3 + 5(1)^2 - (1) - 6
    y=2+5−1−6=0y = 2 + 5 - 1 - 6 = 0

    For x=2x = 2:
    −x=−(2)=−2-x = -(2) = -2
    y=16+20−2−6=28y = 16 + 20 - 2 - 6 = 28

  2. Complete the table with the calculated values.

    x-4-3-2-1012
    2x32x^3-128-54-16-20216
    5x25x^280452050520
    -x43-2-10-1-2
    -6-6-6-6-6-6-6-6
    y-50-12-0-2-6-0-28

    The completed table is:

    x−4−3−2−10122x3−128−54-16-202165x280452050520−x43210−1-2−6−6−6−6−6−6−6−6y−50-120-2-6028\begin{array}{|c|c|c|c|c|c|c|c|} \hline \text{x} & -4 & -3 & -2 & -1 & 0 & 1 & 2 \\ \hline 2x^3 & -128 & -54 & \textbf{-16} & \textbf{-2} & 0 & 2 & 16 \\ \hline 5x^2 & 80 & 45 & 20 & 5 & 0 & 5 & 20 \\ \hline -x & 4 & 3 & \textbf{2} & \textbf{1} & 0 & -1 & \textbf{-2} \\ \hline -6 & -6 & -6 & -6 & -6 & -6 & -6 & -6 \\ \hline \text{y} & -50 & \textbf{-12} & \textbf{0} & \textbf{-2} & \textbf{-6} & \textbf{0} & \textbf{28} \\ \hline \end{array}
Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp