Find the mode of the following frequency distribution: Variable 10 20 30 40 50 Frequency 4 13 16 12 5

Computer Science

ScanSolve AI Answer

Answer

24.29

Step-by-step solution

3 steps
  1. Identify the modal class.

    The modal class is the class with the highest frequency.
    From the given data:

    VariableFrequency
    0-104
    10-2013
    20-3016
    30-4012
    40-505

    The highest frequency is 16, which corresponds to the class interval 20-30.
    So, the modal class is 20-30.

  2. Identify the values for the mode formula.

    The formula for the mode of a grouped frequency distribution is:

    Mode=L+(f1−f02f1−f0−f2)×h\text{Mode} = L + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h

    Where:

    • LL = Lower limit of the modal class = 20
    • f1f_1 = Frequency of the modal class = 16
    • f0f_0 = Frequency of the class preceding the modal class = 13
    • f2f_2 = Frequency of the class succeeding the modal class = 12
    • hh = Class size (upper limit - lower limit) = 30−20=1030 - 20 = 10
  3. Substitute the values into the formula and calculate the mode.

    Mode=20+(16−132(16)−13−12)×10\text{Mode} = 20 + \left( \frac{16 - 13}{2(16) - 13 - 12} \right) \times 10 Mode=20+(332−13−12)×10\text{Mode} = 20 + \left( \frac{3}{32 - 13 - 12} \right) \times 10 Mode=20+(319−12)×10\text{Mode} = 20 + \left( \frac{3}{19 - 12} \right) \times 10 Mode=20+(37)×10\text{Mode} = 20 + \left( \frac{3}{7} \right) \times 10 Mode=20+307\text{Mode} = 20 + \frac{30}{7} Mode=20+4.2857...\text{Mode} = 20 + 4.2857... Mode≈24.29\text{Mode} \approx 24.29

    The mode of the frequency distribution is 24.29.

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