Required Calculations: Battery Bank Sizing:Calculate the required Amp-hour (Ah) capacity Controller requirements). , and how many inparallel(NP , to match the 24V system (considering Charge Total Array Capacity:Determine the total Watt-peak (Wp)required Module Configuration:Calculate the total number of panels(Ntotal). for the solar array. Determine how many must be inseries(NS of the battery bank assuming a 50% Depth of Discharge(DOD).

First, determine the total daily energy that the solar array must generate, accounting for system losses.

$$E_{generated} = \frac{\text{Daily Energy Requirement}}{\text{System Efficiency}} = \frac{4.8 \text{ kWh/day}}{0.8} = 6 \text{ kWh/day} = 6000 \text{ Wh/day}$$

Next, calculate the total Watt-peak (Wp) required for the solar array using the average peak sun hours (PSH).

$$P_{array} = \frac{E_{generated}}{\text{PSH}} = \frac{6000 \text{ Wh/day}}{5 \text{ hours/day}} = 1200 \text{ Wp}$$

The total array capacity required is $\boxed{\text{1200 Wp}}$.

Given:

• Total Array Capacity ($P_{array}$): $1200 \text{ Wp}$
• Solar Panel Max Power ($P_{max}$): $300 \text{ Wp}$
• System Voltage ($V_{sys}$): $24 \text{ V DC}$
• Solar Panel Voltage at Max Power ($V_{mp}$): $32 \text{ V}$

Calculate the total number of panels ($N_{total}$).

$$N_{total} = \frac{P_{array}}{P_{max, panel}} = \frac{1200 \text{ Wp}}{300 \text{ Wp/panel}} = 4 \text{ panels}$$

Determine the number of panels in series ($N_s$). For a 24V system, a single panel with $V_{mp} = 32 \text{ V}$ is suitable for charging via an MPPT charge controller.

$$N_s = 1 \text{ panel/string}$$

Determine the number of parallel strings ($N_p$).

$$N_p = \frac{N_{total}}{N_s} = \frac{4 \text{ panels}}{1 \text{ panel/string}} = 4 \text{ strings}$$

The module configuration is $\boxed{\text{4 total panels}}$, with $\boxed{\text{1 panel in series}}$ per string and $\boxed{\text{4 strings in parallel}}$.

Given:

• Daily Energy Requirement ($E_L$): $4.8 \text{ kWh/day}$
• System Voltage ($V_{sys}$): $24 \text{ V DC}$
• Autonomy: $2 \text{ days}$
• Depth of Discharge (DOD): $50\% = 0.5$

First, calculate the daily energy requirement in Amp-hours (Ah).

$$E_{L, Ah} = \frac{E_L \times 1000 \text{ Wh/kWh}}{V_{sys}} = \frac{4.8 \text{ kWh/day} \times 1000 \text{ Wh/kWh}}{24 \text{ V}} = 200 \text{ Ah/day}$$

Now, calculate the required battery bank capacity, considering autonomy and DOD.

$$\text{Battery Capacity (Ah)} = \frac{E_{L, Ah} \times \text{Autonomy}}{\text{DOD}} = \frac{200 \text{ Ah/day} \times 2 \text{ days}}{0.5} = 800 \text{ Ah}$$

The required battery bank capacity is $\boxed{\text{800 Ah}}$.

Given:

• Number of parallel strings ($N_p$): 4
• Solar Panel Current at Max Power ($I_{mp}$): $9.38 \text{ A}$
• Safety Factor: 1.25 (standard practice for continuous current)

Calculate the maximum current from the solar array.

$$I_{array, max} = N_p \times I_{mp} = 4 \text{ strings} \times 9.38 \text{ A/string} = 37.52 \text{ A}$$

Determine the minimum current rating for the Charge Controller, applying a safety factor.

$$\text{Charge Controller Rating} = I_{array, max} \times \text{Safety Factor} = 37.52 \text{ A} \times 1.25 = 46.9 \text{ A}$$

The minimum current rating required for the Charge Controller is $\boxed{\text{46.9 A}}$.