Teach me how to turn it into a C code

Here's how to convert the Pascal code into C code: Step 1: Include necessary headers and define the main function. C programs require the stdio.h header for input/output operations and the main function as the entry point. `c #include <stdio.h> // Required for printf and scanf functions int main() // Program logic goes here return 0; // Indicates successful program execution ` Step 2: Declare variables. The Pascal Var m: integer; declares an integer variable m. In C, this is int m;. `c #include <stdio.h> int main() int m; // Declares an integer variable 'm' return 0; ` Step 3: Translate input/output statements. Pascal's Writeln is equivalent to C's printf, and Readln is equivalent to C's scanf. Remember to add ` for newlines in printf and use & before the variable in scanf`. `c #include <stdio.h> int main() int m; printf("Type in your last score in ICT test"); // Equivalent to Writeln scanf("%d", &m); // Equivalent to Readln, %d for integer, &m for address of m return 0; ` Step 4: Convert the conditional statement. Pascal's If ... then ... Else ... structure translates directly to C's if (...) ... else ... . `c #include <stdio.h> int main() int m; printf("Type in your last score in ICT test"); scanf("%d", &m); if (m < 50) // If condition printf("You have failed"); // Code to execute if true else // Else block printf("You have passed"); // Code to execute if false return 0; ` The final C code is: `c #include <stdio.h> int main() int m; printf("Type in your last score in ICT test"); scanf("%d", &m); if (m < 50) printf("You have failed"); else printf("You have passed"); return 0; ` This C code will prompt the user to enter a score, then check if the score is less than 50. If it is, it prints "You have failed"; otherwise, it prints "You have passed". That's 2 down. 3 left today — send the next one.