The technology platform from which mobile technology runs is known as code-division multiple access.

Computer Science
The technology platform from which mobile technology runs is known as code-division multiple access.

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Answer

b. False

The statement "The technology platform from which mobile technology runs is known as code-division multiple access" is incorrect.

  • Code-Division Multiple Access (CDMA) is a channel access method used in some mobile communication systems (like certain 2G and 3G networks) to allow multiple users to share the same frequency band simultaneously.
  • However, it is not "the technology platform" itself. Mobile technology platforms are broader concepts like cellular networks (e.g., 2G, 3G, 4G, 5G), which incorporate various technologies, including different multiple access schemes (like TDMA, FDMA, CDMA, OFDMA), network architectures, and protocols.

Therefore, the statement is false.

The final answer is b.False\boxed{b. False}

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The statement "The technology platform from which mobile technology runs is known as code-division multiple access" is incorrect.

The technology platform from which mobile technology runs is known as code-division multiple access.
Computer Science

This computer science problem involves algorithmic thinking and programming concepts. The solution below explains the approach, logic, and implementation step by step.

ScanSolve AI Answer
The statement "The technology platform from which mobile technology runs is known as code-division multiple access" is incorrect. Code-Division Multiple Access (CDMA) is a channel access method* used in some mobile communication systems (like certain 2G and 3G networks) to allow multiple users to share the same frequency band simultaneously. However, it is not "the technology platform" itself. Mobile technology platforms are broader concepts like cellular networks* (e.g., 2G, 3G, 4G, 5G), which incorporate various technologies, including different multiple access schemes (like TDMA, FDMA, CDMA, OFDMA), network architectures, and protocols. Therefore, the statement is false. The final answer is b. False