Trace the execution of the following C code and determine its output: int x = 10; int y = ++x; x = y--; printf("%d %d", x, y);

An integer variable x is initialized to 10.
An integer variable y is declared.

• Initially: $x = 10$, $y$ is undefined.

The ++x is a pre-increment operator. This means x is incremented first, then its new value is assigned to y.

• x becomes $10 + 1 = 11$.
• y is assigned the new value of x, so $y = 11$.
• After this step: $x = 11$, $y = 11$.

The y-- is a post-decrement operator. This means the current value of y is assigned to x first, then y is decremented.

• The current value of y (11) is assigned to x, so $x = 11$.
• Then, y is decremented, so $y$ becomes $11 - 1 = 10$.
• After this step: $x = 11$, $y = 10$.

The printf("%d %d", x, y); statement prints the integer values of x and y separated by a space.

• The value of x is 11.
• The value of y is 10.

The output will be:

$$\text{11 10}$$