Trace the output of the following C code: char ch = 'A'; printf("ASCII of %c is %d", ch, ch);

Question

ScanSolve AI Tutor · Accepted Answer

Here's the trace out put for the given C code:

Initialize the variable.
A char variable ch is declared and assigned the character 'A'.
Interpret the printf format specifiers.
The printf statement uses two format specifiers:
- "%c": This prints the character value of the corresponding argument.
- "%d": This prints the integer (ASCII) value of the corresponding argument.
Substitute the values.
The first ch is printed as a character (%c), which is 'A'.
The second ch is printed as an integer (%d). The ASCII value of 'A' is 65.
Construct the final output.
The string "ASCII of %c is %d" will be printed with 'A' replacing "%c" and 65 replacing "%d".

The output will be:
$\text{ASCII of A is 65}$

Answer