βœ… Very good! 🎊 🟩🟩🟩🟩 🎯 Congratulations! You reached Level 1 by solving 3️⃣ questions correctly! πŸ‘ Keep answering questions to level up again. πŸš€ Next question: What is 1100β‚‚ Γ· 10β‚‚ in binary? A: 1000 remainder 11 B: 111 remainder 10 C: 110 remainder 0 D: 1001 remainder 1

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Answer

C:Β 110Β remainderΒ 0\text{C: } 110 \text{ remainder } 0

to divide 110021100_2 by 10210_2 in binary, we perform binary long division.

Step 1: Set up the long division.

1102102)11002β€Ύ\begin{array}{r} 110_2 \\[-3pt] 10_2 \overline{\smash) 1100_2} \\[-3pt] \end{array}

Step 2: Divide the first part of the dividend (11211_2) by the divisor (10210_2).
10210_2 goes into 11211_2 one time (121_2). Write 121_2 in the quotient.
Multiply 12Γ—102=1021_2 \times 10_2 = 10_2.
Subtract 10210_2 from 11211_2: 112βˆ’102=01211_2 - 10_2 = 01_2.

1002102)11002β€Ύβˆ’10002β€Ύ01002\begin{array}{r} 1\phantom{00_2} \\[-3pt] 10_2 \overline{\smash) 1100_2} \\[-3pt] \underline{-10\phantom{00_2}} \\[-3pt] 01\phantom{00_2} \\[-3pt] \end{array}

Step 3: Bring down the next digit (020_2) from the dividend. We now have 0102010_2.
Divide 0102010_2 (which is 10210_2) by 10210_2.
10210_2 goes into 10210_2 one time (121_2). Write 121_2 in the quotient.
Multiply 12Γ—102=1021_2 \times 10_2 = 10_2.
Subtract 10210_2 from 10210_2: 102βˆ’102=00210_2 - 10_2 = 00_2.

1102102)11002β€Ύβˆ’10002β€Ύ01002βˆ’1002β€Ύ0002\begin{array}{r} 11\phantom{0_2} \\[-3pt] 10_2 \overline{\smash) 1100_2} \\[-3pt] \underline{-10\phantom{00_2}} \\[-3pt] 010\phantom{0_2} \\[-3pt] \underline{-10\phantom{0_2}} \\[-3pt] 00\phantom{0_2} \\[-3pt] \end{array}

Step 4: Bring down the last digit (020_2) from the dividend. We now have 0002000_2.
Divide 0002000_2 by 10210_2.
10210_2 goes into 0002000_2 zero times (020_2). Write 020_2 in the quotient.
Multiply 02Γ—102=0020_2 \times 10_2 = 00_2.
Subtract 00200_2 from 00200_2: 002βˆ’002=00200_2 - 00_2 = 00_2.

1102102)11002β€Ύβˆ’10002β€Ύ01002βˆ’1002β€Ύ0002βˆ’002β€Ύ002\begin{array}{r} 110_2 \\[-3pt] 10_2 \overline{\smash) 1100_2} \\[-3pt] \underline{-10\phantom{00_2}} \\[-3pt] 010\phantom{0_2} \\[-3pt] \underline{-10\phantom{0_2}} \\[-3pt] 000_2 \\[-3pt] \underline{-00_2} \\[-3pt] 00_2 \\[-3pt] \end{array}

The quotient is 1102110_2 and the remainder is 020_2.

The final answer is C:Β 110Β remainderΒ 0\text{C: } 110 \text{ remainder } 0.

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