We read your photo as:

Calculate the waiting times and average waiting time for processes P1, P2, P3, and P4 using the First Come First Served (FCFS) scheduling algorithm. Given arrival times and burst times, determine the

Computer Science

ScanSolve AI Answer

Answer

8.75\text{8.75}

Step-by-step solution

5 steps

here's the calculation for the waiting times and average waiting time using the First Come First Served (FCFS) scheduling algorithm, considering both burst times and arrival times.

In FCFS, processes are executed in the order they arrive. If a process arrives while the CPU is busy, it waits. The waiting time for a process is the time it spends in the ready queue before its execution begins.

Given Data:

ProcessArrival Time (ATAT)Burst Time (BTBT)
P1015
P241
P353
P464

We will calculate the Start Time (STST), Completion Time (CTCT), and Waiting Time (WTWT) for each process.
The formula for Start Time is STi=max⁡(ATi,CTi−1)ST_i = \max(AT_i, CT_{i-1}) (where CT0=0CT_0 = 0).
The formula for Completion Time is CTi=STi+BTiCT_i = ST_i + BT_i.
The formula for Waiting Time is WTi=STi−ATiWT_i = ST_i - AT_i.

  1. Calculate waiting time for P1.

    P1 arrives at time 0 and is the first process.

    ST1=AT1=0ST_1 = AT_1 = 0 CT1=ST1+BT1=0+15=15CT_1 = ST_1 + BT_1 = 0 + 15 = 15 WT1=ST1−AT1=0−0=0WT_1 = ST_1 - AT_1 = 0 - 0 = 0
  2. Calculate waiting time for P2.

    P2 arrives at time 4. P1 completes at time 15. P2 must wait until P1 finishes.

    ST2=max⁡(AT2,CT1)=max⁡(4,15)=15ST_2 = \max(AT_2, CT_1) = \max(4, 15) = 15 CT2=ST2+BT2=15+1=16CT_2 = ST_2 + BT_2 = 15 + 1 = 16 WT2=ST2−AT2=15−4=11WT_2 = ST_2 - AT_2 = 15 - 4 = 11
  3. Calculate waiting time for P3.

    P3 arrives at time 5. P2 completes at time 16. P3 must wait until P2 finishes.

    ST3=max⁡(AT3,CT2)=max⁡(5,16)=16ST_3 = \max(AT_3, CT_2) = \max(5, 16) = 16 CT3=ST3+BT3=16+3=19CT_3 = ST_3 + BT_3 = 16 + 3 = 19 WT3=ST3−AT3=16−5=11WT_3 = ST_3 - AT_3 = 16 - 5 = 11
  4. Calculate waiting time for P4.

    P4 arrives at time 6. P3 completes at time 19. P4 must wait until P3 finishes.

    ST4=max⁡(AT4,CT3)=max⁡(6,19)=19ST_4 = \max(AT_4, CT_3) = \max(6, 19) = 19 CT4=ST4+BT4=19+4=23CT_4 = ST_4 + BT_4 = 19 + 4 = 23 WT4=ST4−AT4=19−6=13WT_4 = ST_4 - AT_4 = 19 - 6 = 13
  5. Calculate the average waiting time.

    The average waiting time is the sum of all waiting times divided by the number of processes.

    Average Waiting Time=WT1+WT2+WT3+WT44\text{Average Waiting Time} = \frac{WT_1 + WT_2 + WT_3 + WT_4}{4} Average Waiting Time=0+11+11+134\text{Average Waiting Time} = \frac{0 + 11 + 11 + 13}{4} Average Waiting Time=354\text{Average Waiting Time} = \frac{35}{4} Average Waiting Time=8.75\text{Average Waiting Time} = \boxed{\text{8.75}}
Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp