Given demand and supply functions Qd = 20 − 2p and Qs = 10 + 3p, determine the equilibrium price and quantity and calculate the point price elasticity of demand at equilibrium.

At equilibrium, $Q_d = Q_s$.

$$20 - 2p = 10 + 3p$$

$$20 - 10 = 3p + 2p$$ $$10 = 5p$$ $$p = \frac{10}{5}$$ $$p = 2$$

The equilibrium price is GH¢2.

Using the demand function:

$$Q_d = 20 - 2(2)$$ $$Q_d = 20 - 4$$ $$Q_d = 16$$

Using the supply function (to verify):

$$Q_s = 10 + 3(2)$$ $$Q_s = 10 + 6$$ $$Q_s = 16$$

The equilibrium quantity is 16 kilos.

The equilibrium price is $\boxed{\text{GH¢2}}$ and the equilibrium quantity is $\boxed{\text{16 kilos}}$.

Given $Q_d = 20 - 2p$, the derivative $\frac{dQ_d}{dp}$ is the coefficient of $p$.

$$\frac{dQ_d}{dp} = -2$$

Equilibrium $p = 2$
Equilibrium $Q_d = 16$

$$E_d = -2 \times \frac{2}{16}$$ $$E_d = -2 \times \frac{1}{8}$$ $$E_d = -\frac{2}{8}$$ $$E_d = -\frac{1}{4}$$ $$E_d = -0.25$$

The point price elasticity of demand at equilibrium is $\boxed{-0.25}$.

Given $Q_s = 10 + 3p$, the derivative $\frac{dQ_s}{dp}$ is the coefficient of $p$.

$$\frac{dQ_s}{dp} = 3$$

Equilibrium $p = 2$
Equilibrium $Q_s = 16$

$$E_s = 3 \times \frac{2}{16}$$ $$E_s = 3 \times \frac{1}{8}$$ $$E_s = \frac{3}{8}$$ $$E_s = 0.375$$

The price elasticity of supply at equilibrium is $\boxed{0.375}$.