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Part b· 2 steps

  1. Describe the bromine water test.

    Ethene, being an unsaturated hydrocarbon, will undergo an addition reaction with bromine water. When brown bromine water is added to ethene, the bromine is consumed, and the solution rapidly decolorizes. Ethane, being a saturated hydrocarbon, will not react with bromine water under normal conditions, so the brown color will persist.

  2. Describe the acidified potassium permanganate test (Baeyer's test).

    Ethene will react with cold, dilute, acidified potassium permanganate solution. The purple color of the permanganate solution will decolorize as ethene is oxidized to a diol. Ethane will not react with acidified potassium permanganate solution, and the purple color will remain.

    • Test 1: Add bromine water. Ethene will decolorize the brown bromine water, while ethane will not.\boxed{\text{Add bromine water. Ethene will decolorize the brown bromine water, while ethane will not.}}
    • Test 2: Add acidified potassium permanganate solution. Ethene will decolorize the purple solution, while ethane will not.\boxed{\text{Add acidified potassium permanganate solution. Ethene will decolorize the purple solution, while ethane will not.}}

    35)

Part a· 4 steps

  1. Identify Process A.

    Process A converts simple sugar to ethanol. This process is known as fermentation.

    • A: Fermentation\boxed{\text{Fermentation}}
  2. Identify Process B.

    Process B converts ethanol to ethene. This involves the removal of water from ethanol, which is dehydration.

    • B: Dehydration\boxed{\text{Dehydration}}
  3. Identify Process C.

    Process C converts ethene to a polymer. This is the process of polymerization.

    • C: Polymerization\boxed{\text{Polymerization}}
  4. Identify Process D.

    Process D converts vegetable oils to soap. This process is called saponification.

    • D: Saponification\boxed{\text{Saponification}}
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