First please solve it properly not in Hindi in English please all question 1 to 21 please first solve this then I will give another work

English

ScanSolve AI Answer

Answer

540\text{540}

Step-by-step solution

5 steps

  1. Identify the given values.

    We are given two numbers, a=60a = 60 and b=108b = 108.
    The HCF (Highest Common Factor) of these numbers is given as 12.
    We need to find the LCM (Least Common Multiple) of these numbers.

  2. Use the relationship between HCF, LCM, and the product of two numbers.

    The formula states that for any two positive integers aa and bb:

    HCF(a,b)×LCM(a,b)=a×b\text{HCF}(a, b) \times \text{LCM}(a, b) = a \times b

  3. Substitute the given values into the formula.

    12×LCM(60,108)=60×10812 \times \text{LCM}(60, 108) = 60 \times 108

  4. Calculate the product of the numbers.

    60×108=648060 \times 108 = 6480

    So, the equation becomes:

    12×LCM(60,108)=648012 \times \text{LCM}(60, 108) = 6480

  5. Solve for the LCM.

    Divide both sides by 12:

    LCM(60,108)=648012\text{LCM}(60, 108) = \frac{6480}{12} LCM(60,108)=540\text{LCM}(60, 108) = 540

    The LCM of 60 and 108 is 540\boxed{\text{540}}.

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