This English question involves literary analysis, grammar, or writing skills. The detailed response below provides a well-structured answer with supporting evidence and clear explanations.
ScanSolve AI Answer
Okay, let's solve these problems in English, following the specified format. a) Real area of the piece of land in km^2 Step 1: Convert the map scale from cm to km. The map scale is 1:250,000, meaning 1 \, cm on the map represents 250,000 \, cm on the ground. We know that 100 \, cm = 1 \, m and 1000 \, m = 1 \, km. So, 250,000 \, cm = (250,000)/(100) \, m = 2,500 \, m. And 2,500 \, m = (2,500)/(1000) \, km = 2.5 \, km. Therefore, 1 \, cm on the map represents 2.5 \, km on the ground. Step 2: Calculate the real area. For area, we square the linear scale. 1 \, cm^2 on the map represents (2.5 \, km)^2 on the ground. (2.5 \, km)^2 = 6.25 \, km^2 The area on the map is 4 \, cm^2. Real area = Area on map × (Area scale factor) Real area = 4 \, cm^2 × 6.25 \, (km^2)/(cm^2) = 25 \, km^2 The real area of the piece of land is 25 km^2. b) Time taken by the tractors to plough 10 acres Step 1: Find the individual ploughing rates for each tractor. Tractor A ploughs 1 acre in 45 minutes. Rate of A (R_A) = 1 \, acre45 \, minutes. Tractor B ploughs 1 acre in 20 minutes. Rate of B (R_B) = 1 \, acre20 \, minutes. Step 2: Find the combined ploughing rate when both tractors work together. Combined rate (R_total) = R_A + R_B R_total = (1)/(45) + (1)/(20) \, acres/minute To add these fractions, find the least common multiple (LCM) of 45 and 20, which is 180. R_total = (1 × 4)/(45 × 4) + (1 × 9)/(20 × 9) = (4)/(180) + (9)/(180) = (13)/(180) \, acres/minute Step 3: Calculate the time required to plough 10 acres. Time = Total areaCombined rate Time = 10 \, acres(13)/(180) \, acres/minute = 10 × (180)/(13) \, minutes = (1800)/(13) \, minutes Step 4: Convert the time to hours and minutes. (1800)/(13) \, minutes ≈ 138.4615 \, minutes 138 minutes is equal to 2 hours and 18 minutes (138 = 2 × 60 + 18). The remaining fraction of a minute is 0.4615 × 60 ≈ 27.69 seconds. The time taken by the tractors to plough 10 acres is approximately 2 hours, 18 minutes and 28 seconds. c) Find the total budget for ploughing Step 1: Express the contributions as fractions of the total budget. Let the total budget be B. Clergy's contribution = (2)/(5) B. MP's contribution = (1)/(4) B. Step 2: Calculate the fraction of the budget remaining after the Clergy's and MP's contributions. Total contributions from Clergy and MP = (2)/(5) B + (1)/(4) B = ((8)/(20) + (5)/(20)) B = (13)/(20) B. Remaining fraction = B - (13)/(20) B = (7)/(20) B. Step 3: Calculate the fraction contributed by the group members. The group members contributed half of the remaining fraction. Group members' contribution = (1)/(2) × (7)/(20) B = (7)/(40) B. Step 4: Calculate the total monetary contribution from the group members. There are 48 group members, and each contributed UGX 50,000. Total contribution from group members = 48 × 50,000 \, UGX = 2,400,000 \, UGX. Step 5: Equate the group members' contribution (as a fraction and in money) to find the total budget. (7)/(40) B = 2,400,000 \, UGX B = 2,400,000 × (40)/(7) \, UGX B = (96,000,000)/(7) \, UGX B ≈ 13,714,285.71 \, UGX Rounding to the nearest shilling. The total budget for ploughing is approximately UGX 13,714,286. That's 2 down. 3 left today — send the next one.