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How to i plot a graph and calculate slope?

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Answer

688.24 Hz⋅m\text{688.24 Hz} \cdot \text{m}

Step-by-step solution

3 steps
  1. Plotting the Graph

    To plot the graph, follow these steps:

    • Draw two perpendicular axes on graph paper.
    • Label the horizontal axis (x-axis) as "1L\frac{1}{L} (m−1^{-1})" and the vertical axis (y-axis) as "Frequency (FF) (Hz)".
    • Choose appropriate scales for both axes so that all data points fit and the graph fills most of the page.
    • Plot the data points from your table:
      • (2.86,288)(2.86, 288)
      • (2.94,320)(2.94, 320)
      • (3.03,384)(3.03, 384)
      • (3.03,426)(3.03, 426)
    • Draw a straight line that best fits the plotted points. This line should pass as close as possible to all points, with roughly an equal number of points above and below it.
  2. Calculating the Slope

    To calculate the slope of the line of best fit:

    • Choose two distinct points on the line of best fit. These points should be far apart to minimize error. Let these points be (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2).
    • Use the formula for the slope (mm): m=ΔyΔx=y2−y1x2−x1m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1}
  3. Slope Calculation using provided data

    Since a line of best fit cannot be drawn here, we will calculate the slope using the first data point and an average of the last two data points (due to the repeated x-value) to represent the trend.

    The points used for calculation are:
    Point 1: (x1,y1)=(2.86 m−1,288 Hz)(x_1, y_1) = (2.86 \text{ m}^{-1}, 288 \text{ Hz})
    Point 2: (x2,y2)=(3.03 m−1,384 Hz+426 Hz2)=(3.03 m−1,405 Hz)(x_2, y_2) = (3.03 \text{ m}^{-1}, \frac{384 \text{ Hz} + 426 \text{ Hz}}{2}) = (3.03 \text{ m}^{-1}, 405 \text{ Hz})

    Now, substitute these values into the slope formula:

    m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1} m=405 Hz−288 Hz3.03 m−1−2.86 m−1m = \frac{405 \text{ Hz} - 288 \text{ Hz}}{3.03 \text{ m}^{-1} - 2.86 \text{ m}^{-1}} m=117 Hz0.17 m−1m = \frac{117 \text{ Hz}}{0.17 \text{ m}^{-1}} m≈688.24 Hz⋅mm \approx 688.24 \text{ Hz} \cdot \text{m}

    The calculated slope is approximately 688.24 Hz⋅m\text{688.24 Hz} \cdot \text{m}.

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