This English question involves literary analysis, grammar, or writing skills. The detailed response below provides a well-structured answer with supporting evidence and clear explanations.
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Here's the solution to the problem with explanations in English: Step 1: Convert the given time from minutes to seconds. t = 10 min × 60 s1 min = 600 s Step 2: Calculate the total charge (Q) passed. Q = I × t Where I is the current and t is the time. Q = 1.5 A × 600 s = 900 C Step 3: Write the half-reaction for the deposition of copper at the cathode. Cu^2+(aq) + 2e^- Cu(s) This reaction shows that 2 moles of electrons are required to deposit 1 mole of copper (Cu). Step 4: Calculate the moles of copper deposited. Faraday's constant (F) is 96485 C/mol e^-. Moles of electrons (n_e) = (Q)/(F) n_e = 900 C96485 C/mol e^- ≈ 0.009328 mol e^- Since 2 moles of electrons deposit 1 mole of copper, the moles of copper deposited (n_Cu) will be: n_Cu = (n_e)/(2) = 0.009328 mol e^-2 ≈ 0.004664 mol Step 5: Calculate the mass of copper deposited. The molar mass of copper is 63.5 g/mol. Mass (m) = Moles × Molar mass m = 0.004664 mol × 63.5 g/mol ≈ 0.2964 g The mass of copper deposited at the cathode is: 0.2964 g That's 2 down. 3 left today — send the next one.