Please solve all thé question paper in english

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Answer

R⃗=−12i⃗+4j⃗−6k⃗ N\vec{R} = -12\vec{i} + 4\vec{j} - 6\vec{k} \text{ N}

MO⃗=22i⃗+42j⃗−16k⃗ N⋅m\vec{M_O} = 22\vec{i} + 42\vec{j} - 16\vec{k} \text{ N}\cdot\text{m}

Step-by-step solution

2 steps

Okay, lekeufackshanif! I'll switch to English for this one and solve part b).

  1. Determine the resultant force R⃗\vec{R}.

    The resultant force R⃗\vec{R} is the vector sum of F1⃗\vec{F_1} and F2⃗\vec{F_2}.
    Given F1⃗=(−8i⃗+8j⃗−4k⃗)\vec{F_1} = (-8\vec{i} + 8\vec{j} - 4\vec{k}) N and F2⃗=(−4i⃗−4j⃗−2k⃗)\vec{F_2} = (-4\vec{i} - 4\vec{j} - 2\vec{k}) N.

    R⃗=F1⃗+F2⃗\vec{R} = \vec{F_1} + \vec{F_2} R⃗=(−8i⃗+8j⃗−4k⃗)+(−4i⃗−4j⃗−2k⃗)\vec{R} = (-8\vec{i} + 8\vec{j} - 4\vec{k}) + (-4\vec{i} - 4\vec{j} - 2\vec{k}) R⃗=(−8−4)i⃗+(8−4)j⃗+(−4−2)k⃗\vec{R} = (-8 - 4)\vec{i} + (8 - 4)\vec{j} + (-4 - 2)\vec{k} R⃗=−12i⃗+4j⃗−6k⃗ N\vec{R} = -12\vec{i} + 4\vec{j} - 6\vec{k} \text{ N}
  2. Determine the moment of R⃗\vec{R} about the origin O.

    Since the forces F1⃗\vec{F_1} and F2⃗\vec{F_2} are concurrent, their resultant R⃗\vec{R} also acts through their point of concurrency.
    From the previous part, the point of concurrency P was found using λ1=916\lambda_1 = \frac{9}{16} with r1⃗\vec{r_1}:

    rP⃗=r1⃗+λ1F1⃗\vec{r_P} = \vec{r_1} + \lambda_1 \vec{F_1} rP⃗=(5i⃗−6j⃗−k⃗)+916(−8i⃗+8j⃗−4k⃗)\vec{r_P} = (5\vec{i} - 6\vec{j} - \vec{k}) + \frac{9}{16}(-8\vec{i} + 8\vec{j} - 4\vec{k}) rP⃗=(5i⃗−6j⃗−k⃗)+(−7216i⃗+7216j⃗−3616k⃗)\vec{r_P} = (5\vec{i} - 6\vec{j} - \vec{k}) + (-\frac{72}{16}\vec{i} + \frac{72}{16}\vec{j} - \frac{36}{16}\vec{k}) rP⃗=(5i⃗−6j⃗−k⃗)+(−92i⃗+92j⃗−94k⃗)\vec{r_P} = (5\vec{i} - 6\vec{j} - \vec{k}) + (-\frac{9}{2}\vec{i} + \frac{9}{2}\vec{j} - \frac{9}{4}\vec{k}) rP⃗=(5−92)i⃗+(−6+92)j⃗+(−1−94)k⃗\vec{r_P} = \left(5 - \frac{9}{2}\right)\vec{i} + \left(-6 + \frac{9}{2}\right)\vec{j} + \left(-1 - \frac{9}{4}\right)\vec{k} rP⃗=(10−92)i⃗+(−12+92)j⃗+(−4−94)k⃗\vec{r_P} = \left(\frac{10 - 9}{2}\right)\vec{i} + \left(\frac{-12 + 9}{2}\right)\vec{j} + \left(\frac{-4 - 9}{4}\right)\vec{k} rP⃗=12i⃗−32j⃗−134k⃗ m\vec{r_P} = \frac{1}{2}\vec{i} - \frac{3}{2}\vec{j} - \frac{13}{4}\vec{k} \text{ m}

    The moment of R⃗\vec{R} about the origin O is given by MO⃗=rP⃗×R⃗\vec{M_O} = \vec{r_P} \times \vec{R}.

    MO⃗=∣i⃗j⃗k⃗12−32−134−124−6∣\vec{M_O} = \begin{vmatrix} \vec{i} & \vec{j} & \vec{k} \\ \frac{1}{2} & -\frac{3}{2} & -\frac{13}{4} \\ -12 & 4 & -6 \end{vmatrix} MO⃗=i⃗((−32)(−6)−(−134)(4))−j⃗((12)(−6)−(−134)(−12))+k⃗((12)(4)−(−32)(−12))\vec{M_O} = \vec{i}\left(\left(-\frac{3}{2}\right)(-6) - \left(-\frac{13}{4}\right)(4)\right) - \vec{j}\left(\left(\frac{1}{2}\right)(-6) - \left(-\frac{13}{4}\right)(-12)\right) + \vec{k}\left(\left(\frac{1}{2}\right)(4) - \left(-\frac{3}{2}\right)(-12)\right) MO⃗=i⃗(9−(−13))−j⃗(−3−(39))+k⃗(2−(18))\vec{M_O} = \vec{i}\left(9 - (-13)\right) - \vec{j}\left(-3 - (39)\right) + \vec{k}\left(2 - (18)\right) MO⃗=i⃗(9+13)−j⃗(−3−39)+k⃗(2−18)\vec{M_O} = \vec{i}(9 + 13) - \vec{j}(-3 - 39) + \vec{k}(2 - 18) MO⃗=22i⃗+42j⃗−16k⃗ N⋅m\vec{M_O} = 22\vec{i} + 42\vec{j} - 16\vec{k} \text{ N}\cdot\text{m}

    The resultant force is R⃗=−12i⃗+4j⃗−6k⃗ N\boxed{\vec{R} = -12\vec{i} + 4\vec{j} - 6\vec{k} \text{ N}}.
    The moment of R⃗\vec{R} about the origin O is MO⃗=22i⃗+42j⃗−16k⃗ N⋅m\boxed{\vec{M_O} = 22\vec{i} + 42\vec{j} - 16\vec{k} \text{ N}\cdot\text{m}}.

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