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Plot the given points on the Cartesian plane.

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Graph of y = x

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Key points of y = x
Pointxy
x-intercept00

Step-by-step solution

12 steps

Part a· 2 steps

On the Cartesian plane below, draw the quadrilateral PQRS with vertices P(4,6), Q(6,3), R(4,4), and S(2,3).

  1. Plot the given points on the Cartesian plane.

    P(4,6)
    Q(6,3)
    R(4,4)
    S(2,3)

  2. Connect the points in order to form the quadrilateral PQRS.

    (This step requires a physical drawing on the provided graph paper, which cannot be done here. The points are plotted as described.)

Part b· 3 steps

Draw P'Q'R'S' the image of PQRS under the transformation defined by the translation vector T=(−7−6)T = \begin{pmatrix} -7 \\ -6 \end{pmatrix}. Write down the coordinates of P'Q'R'S'.

  1. Apply the translation vector to each vertex of PQRS.

    For a point (x,y)(x, y) and a translation vector (ab)\begin{pmatrix} a \\ b \end{pmatrix}, the image is (x+a,y+b)(x+a, y+b).

    P'(x', y') = P(4,6) + (−7−6)\begin{pmatrix} -7 \\ -6 \end{pmatrix} = (4−7,6−6)(4-7, 6-6) = (−3,0)(-3, 0)
    Q'(x', y') = Q(6,3) + (−7−6)\begin{pmatrix} -7 \\ -6 \end{pmatrix} = (6−7,3−6)(6-7, 3-6) = (−1,−3)(-1, -3)
    R'(x', y') = R(4,4) + (−7−6)\begin{pmatrix} -7 \\ -6 \end{pmatrix} = (4−7,4−6)(4-7, 4-6) = (−3,−2)(-3, -2)
    S'(x', y') = S(2,3) + (−7−6)\begin{pmatrix} -7 \\ -6 \end{pmatrix} = (2−7,3−6)(2-7, 3-6) = (−5,−3)(-5, -3)

  2. Write down the coordinates of P'Q'R'S'.

    The coordinates are:
    P' = (−3,0)\boxed{(-3, 0)}
    Q' = (−1,−3)\boxed{(-1, -3)}
    R' = (−3,−2)\boxed{(-3, -2)}
    S' = (−5,−3)\boxed{(-5, -3)}

  3. Draw the image P'Q'R'S' on the same Cartesian plane.

    (This step requires a physical drawing on the provided graph paper, which cannot be done here. The points are plotted as described.)

Part c· 3 steps

P''Q''R''S'' is the image of P'Q'R'S' when reflected in the line y=1y=1. On the same plane, draw P''Q''R''S''.

  1. Apply the reflection in the line y=1y=1 to each vertex of P'Q'R'S'.

    For a reflection in the line y=ky=k, a point (x,y)(x, y) maps to (x,2k−y)(x, 2k-y). Here k=1k=1.
    So, (x,y)→(x,2(1)−y)=(x,2−y)(x, y) \to (x, 2(1)-y) = (x, 2-y).

    P'' = P'(-3, 0) →(−3,2−0)\to (-3, 2-0) = (−3,2)(-3, 2)
    Q'' = Q'(-1, -3) →(−1,2−(−3))\to (-1, 2-(-3)) = (−1,2+3)(-1, 2+3) = (−1,5)(-1, 5)
    R'' = R'(-3, -2) →(−3,2−(−2))\to (-3, 2-(-2)) = (−3,2+2)(-3, 2+2) = (−3,4)(-3, 4)
    S'' = S'(-5, -3) →(−5,2−(−3))\to (-5, 2-(-3)) = (−5,2+3)(-5, 2+3) = (−5,5)(-5, 5)

  2. Write down the coordinates of P''Q''R''S''.

    The coordinates are:
    P'' = (−3,2)\boxed{(-3, 2)}
    Q'' = (−1,5)\boxed{(-1, 5)}
    R'' = (−3,4)\boxed{(-3, 4)}
    S'' = (−5,5)\boxed{(-5, 5)}

  3. Draw the image P''Q''R''S'' on the same Cartesian plane.

    (This step requires a physical drawing on the provided graph paper, which cannot be done here. The points are plotted as described.)

Part d· 4 steps

Draw P'''Q'''R'''S''' the image P''Q''R''S'' when reflected in the line y−x=0y-x=0.

  1. Understand the reflection line.

    The line y−x=0y-x=0 is equivalent to y=xy=x.

  2. Apply the reflection in the line y=xy=x to each vertex of P''Q''R''S''.

    For a reflection in the line y=xy=x, a point (x,y)(x, y) maps to (y,x)(y, x).

    P''' = P''(-3, 2) →(2,−3)\to (2, -3)
    Q''' = Q''(-1, 5) →(5,−1)\to (5, -1)
    R''' = R''(-3, 4) →(4,−3)\to (4, -3)
    S''' = S''(-5, 5) →(5,−5)\to (5, -5)

  3. Write down the coordinates of P'''Q'''R'''S'''.

    The coordinates are:
    P''' = (2,−3)\boxed{(2, -3)}
    Q''' = (5,−1)\boxed{(5, -1)}
    R''' = (4,−3)\boxed{(4, -3)}
    S''' = (5,−5)\boxed{(5, -5)}

  4. Draw the image P'''Q'''R'''S''' on the same Cartesian plane.

    (This step requires a physical drawing on the provided graph paper, which cannot be done here. The points are plotted as described.)

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