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  1. Find four rational numbers between 1 and 2.
  1. To find four rational numbers between 1 and 2, we can express them as fractions with a common denominator.

    Since we need to find n=4n=4 rational numbers, we multiply the numerator and denominator by (n+1)=5(n+1)=5.

    1=1×55=551 = \frac{1 \times 5}{5} = \frac{5}{5} 2=2×55=1052 = \frac{2 \times 5}{5} = \frac{10}{5}
  2. Now, we can easily find four rational numbers between 55\frac{5}{5} and 105\frac{10}{5}.

    65,75,85,95\frac{6}{5}, \frac{7}{5}, \frac{8}{5}, \frac{9}{5}

    Answer: 65,75,85,95\boxed{\frac{6}{5}, \frac{7}{5}, \frac{8}{5}, \frac{9}{5}}

    1. Find five rational numbers between 35\frac{3}{5} and 45\frac{4}{5}.
  3. To find five rational numbers between 35\frac{3}{5} and 45\frac{4}{5}, we express them as fractions with a common denominator.

    Since we need to find n=5n=5 rational numbers, we multiply the numerator and denominator by (n+1)=6(n+1)=6.

    35=3×65×6=1830\frac{3}{5} = \frac{3 \times 6}{5 \times 6} = \frac{18}{30} 45=4×65×6=2430\frac{4}{5} = \frac{4 \times 6}{5 \times 6} = \frac{24}{30}
  4. Now, we can easily find five rational numbers between 1830\frac{18}{30} and 2430\frac{24}{30}.

    1930,2030,2130,2230,2330\frac{19}{30}, \frac{20}{30}, \frac{21}{30}, \frac{22}{30}, \frac{23}{30}

    Answer: 1930,2030,2130,2230,2330\boxed{\frac{19}{30}, \frac{20}{30}, \frac{21}{30}, \frac{22}{30}, \frac{23}{30}}

    1. Locate 3\sqrt{3} on the number line.
  5. Draw a number line.

    Mark point O at 0 and point A at 1.

  6. At point A, draw a perpendicular line segment AB of length 1 unit.

  7. Join O and B.

    By the Pythagorean theorem, the length of OB is OA2+AB2=12+12=2\sqrt{OA^2 + AB^2} = \sqrt{1^2 + 1^2} = \sqrt{2}.

  8. At point B, draw a perpendicular line segment BC of length 1 unit to OB.

  9. Join O and C.

    By the Pythagorean theorem, the length of OC is OB2+BC2=(2)2+12=2+1=3\sqrt{OB^2 + BC^2} = \sqrt{(\sqrt{2})^2 + 1^2} = \sqrt{2+1} = \sqrt{3}.

  10. With O as the center and OC as the radius, draw an arc that intersects the number line.

    This intersection point represents 3\sqrt{3}.

    Answer: Follow the steps above to locate 3 on the number line.\boxed{\text{Follow the steps above to locate } \sqrt{3} \text{ on the number line.}}

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