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Step-by-step solution

4 steps
  1. Compare the given polynomial x2+x+1x^2 + x + 1 with the standard quadratic polynomial ax2+bx+cax^2 + bx + c.

    Here, a=1a=1, b=1b=1, and c=1c=1.

  2. Find the sum of the roots α+β\alpha + \beta.

    The sum of the roots is given by the formula: α+β=−ba\alpha + \beta = -\frac{b}{a}

    α+β=−11=−1\alpha + \beta = -\frac{1}{1} = -1
  3. Find the product of the roots αβ\alpha \beta.

    The product of the roots is given by the formula: αβ=ca\alpha \beta = \frac{c}{a}

    αβ=11=1\alpha \beta = \frac{1}{1} = 1
  4. Find the value of 1α+1β\frac{1}{\alpha} + \frac{1}{\beta}.

    First, simplify the expression:

    1α+1β=β+ααβ\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\beta + \alpha}{\alpha \beta}

    Now, substitute the values obtained from Step 2 and Step 3:

    1α+1β=−11=−1\frac{1}{\alpha} + \frac{1}{\beta} = \frac{-1}{1} = -1

    Therefore, the value of α+β\alpha + \beta is −1-1 and the value of 1α+1β\frac{1}{\alpha} + \frac{1}{\beta} is −1-1.

    α+β=−1,1α+1β=−1\boxed{\alpha + \beta = -1, \quad \frac{1}{\alpha} + \frac{1}{\beta} = -1}

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