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ScanSolve AI Answer
Step 1: Find the value of the unknown resistance R In the given circuit, it is a Wheatstone bridge. It is stated that no current flows through the 4 resistor (between B and D). This means the bridge is balanced. The condition for a balanced Wheatstone bridge is: R_ABR_BC = R_ADR_DC From the diagram, the resistances are: R_AB = 1 R_BC = R R_AD = 1 R_DC = 1 Substituting these values into the balance condition: (1)/(R) = (1)/(1) 1 = (R)/(1) R = 1 Step 2: Find the potential difference across A and D (V_AD) Since the bridge is balanced, no current flows through the 4 resistor. Therefore, we can ignore this resistor for current calculations in the main branches. The total potential difference across A and C is V_AC = 2V. The resistances in the lower branch (ADC), R_AD and R_DC, are in series. R_AD = 1 R_DC = 1 The total resistance of the lower branch is R_lower = R_AD + R_DC = 1 + 1 = 2. The current flowing through the lower branch (ADC), I_ADC, is: I_ADC = V_ACR_lower = (2V)/(2) = 1A The potential difference across A and D (V_AD) can be found using Ohm's law: V_AD = I_ADC × R_AD V_AD = 1A × 1 V_AD = 1V That's 2 down. 3 left today — send the next one.