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f

2.243 m2.243 \text{ m}

Step-by-step solution

3 steps

here are the remaining parts of ITEM 3 from the image:

Part f· 3 steps

Calculate the wavelength of emitted sound wave.

  1. Identify the given values and the necessary frequency.

    The problem states the speed of sound in air is 340 m/s340 \text{ m/s}.
    We will assume the emitted sound wave has the same frequency as the fundamental frequency of the string, which was calculated in part b) as f1≈151.52 Hzf_1 \approx 151.52 \text{ Hz}.
    Given:
    Speed of sound in air, Vsound=340 m/sV_{sound} = 340 \text{ m/s}
    Frequency of emitted sound, f=151.52 Hzf = 151.52 \text{ Hz}

  2. Use the wave speed formula to calculate the wavelength.

    The relationship between wave speed (VV), frequency (ff), and wavelength (λ\lambda) is V=fλV = f\lambda.
    Rearranging for wavelength:

    λ=Vf\lambda = \frac{V}{f}
  3. Substitute the values and calculate the wavelength.

    λ=340 m/s151.52 Hz\lambda = \frac{340 \text{ m/s}}{151.52 \text{ Hz}} λ≈2.243 m\lambda \approx 2.243 \text{ m}

    The wavelength of the emitted sound wave is 2.243 m\boxed{2.243 \text{ m}}.

Part g

Calculate the maximum

This part of the question is incomplete as the quantity to be maximized is not specified. Therefore, it cannot be solved.

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