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Define variables for the dimensions of the rectangular plot.

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2 parts
a

w2+3w−180=0w^2 + 3w - 180 = 0

b

Width=12 m,Length=15 m\text{Width} = 12 \text{ m}, \text{Length} = 15 \text{ m}

Step-by-step solution

10 steps

Part a· 4 steps

Form quadratic equation to represent this situation.

  1. Define variables for the dimensions of the rectangular plot.

    Let ww be the width of the plot in meters.
    Let ll be the length of the plot in meters.

  2. Express the length in terms of the width.

    The problem states that the length of the plot is 3 meters more than its width.

    l=w+3l = w + 3
  3. Use the given area to form an equation.

    The area of a rectangle is given by A=l×wA = l \times w.
    The total area is 180 m2180 \text{ m}^2.
    Substitute the expressions for ll and AA:

    180=(w+3)w180 = (w+3)w
  4. Expand and rearrange the equation into standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.

    180=w2+3w180 = w^2 + 3w

    Subtract 180 from both sides:

    w2+3w−180=0w^2 + 3w - 180 = 0

    The quadratic equation is:

    w2+3w−180=0\boxed{w^2 + 3w - 180 = 0}

Part b

Width=12 m,Length=15 m\text{Width} = 12 \text{ m}, \text{Length} = 15 \text{ m}

Solve the equation by factorisation method to find the dimensions of the plot.

  1. Factor the quadratic equation w2+3w−180=0w^2 + 3w - 180 = 0.

    We need to find two numbers that multiply to -180 and add up to 3.
    These numbers are 15 and -12.

    15×(−12)=−18015 \times (-12) = -180 15+(−12)=315 + (-12) = 3
  2. Rewrite the middle term using these two numbers.

    w2+15w−12w−180=0w^2 + 15w - 12w - 180 = 0
  3. Factor by grouping.

    w(w+15)−12(w+15)=0w(w + 15) - 12(w + 15) = 0 (w−12)(w+15)=0(w - 12)(w + 15) = 0
  4. Solve for ww.

    Set each factor equal to zero:

    w−12=0  ⟹  w=12w - 12 = 0 \implies w = 12 w+15=0  ⟹  w=−15w + 15 = 0 \implies w = -15
  5. Determine the valid width.

    Since width cannot be negative, we discard w=−15w = -15.
    Therefore, the width of the plot is w=12 mw = 12 \text{ m}.

  6. Calculate the length of the plot.

    Using the relationship l=w+3l = w + 3:

    l=12+3l = 12 + 3 l=15 ml = 15 \text{ m}

    The dimensions of the plot are:

    Width=12 m,Length=15 m\boxed{\text{Width} = 12 \text{ m}, \text{Length} = 15 \text{ m}}
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