Identify the type of scale used on the map and calculate the actual distance between Jansenville and Port Shepstone, given that 250 pixels on the scale bar represents 100 km.

4.1.1

Step 1: Observe the map to identify the type of scale used.
The map displays a bar scale (also known as a graphic scale or linear scale) at the bottom right, which visually represents distances.

• Bar scale (or Graphic scale / Linear scale)

4.1.2

Step 1: Determine the actual distance between Jansenville and Port Shepstone using the provided bar scale.
On the map, the bar scale indicates that a certain length represents $100 \text{ km}$. By measuring the distance between Jansenville and Port Shepstone on the map and comparing it to the bar scale, we can calculate the actual distance.
Using a digital measurement tool, the $100 \text{ km}$ segment of the scale bar measures approximately 250 pixels.
The straight-line distance between Jansenville and Port Shepstone on the map measures approximately 1476.48 pixels.

Step 2: Calculate the actual distance.
The scale factor is $\frac{100 \text{ km}}{250 \text{ pixels}} = 0.4 \text{ km/pixel}$.
Actual distance $= 1476.48 \text{ pixels} \times 0.4 \text{ km/pixel} = 590.592 \text{ km}$.
Rounding to the nearest whole number, the actual distance is $591 \text{ km}$.

$$\text{Actual distance} = \left( \frac{\text{Distance on map in pixels}}{\text{Scale bar length in pixels}} \right) \times \text{Actual distance represented by scale bar}$$ $$\text{Actual distance} = \left( \frac{1476.48 \text{ pixels}}{250 \text{ pixels}} \right) \times 100 \text{ km}$$ $$\text{Actual distance} = 5.90592 \times 100 \text{ km}$$ $$\text{Actual distance} = 590.592 \text{ km}$$ $$\text{Actual distance} \approx \boxed{\text{591 km}}$$

4.1.3

Step 1: Use the formula $s = \frac{d}{t}$ to calculate the time ($t$).
We are given the average speed ($s = 120 \text{ km/h}$) and the distance ($d = 591 \text{ km}$) from Question 4.1.2.
Rearrange the formula to solve for time: $t = \frac{d}{s}$.

$$t = \frac{591 \text{ km}}{120 \text{ km/h}}$$ $$t = 4.925 \text{ hours}$$

Step 2: Convert the time into hours and minutes.
The time is 4 full hours.
To find the minutes, multiply the decimal part by 60:

$$\text{Minutes} = 0.925 \times 60$$ $$$$