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Study the diagram below then answer the items (i-v) that follow

Geography

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2 parts
b(iv)

7:00 A.M.\text{}7:00 \text{ A.M.}

b(v)

41∘F\text{}41^\circ \text{F}

Step-by-step solution

7 steps

Haya hapa majibu ya maswali yako:

7.

Part i

Mistari inayoonyeshwa kwenye mchoro hapo juu inaitwa longitudo (meridians).

Part ii

Jina la mstari uliowekwa alama C ni Prime Meridian (Longitudo Sifuri).

Part iii

Matumizi mawili ya mistari iliyoonyeshwa hapo juu ni

Part a

Kutambua longitudo** ya eneo.

Part b(iv)

7:00 A.M.\text{}7:00 \text{ A.M.}

Ikiwa ni saa 3:00 P.M. katika mji ulioko kwenye mstari E, saa ngapi itakuwa katika mji ulioko kwenye mstari A?

Kutambua saa za maeneo mbalimbali** na tarehe (kupitia International Date Line).

  1. Tambua longitudo za mistari A na E.

    • Mstari E uko kwenye 60∘60^\circ Mashariki.
    • Mstari A uko kwenye 60∘60^\circ Magharibi.

  2. Kokotoa tofauti ya longitudo kati ya A na E.

    Tofauti ya longitudo = 60∘ (Mashariki)+60∘ (Magharibi)=120∘60^\circ \text{ (Mashariki)} + 60^\circ \text{ (Magharibi)} = 120^\circ.

  3. Kokotoa tofauti ya saa.

    Tunajua kwamba 15∘15^\circ ya longitudo ni sawa na saa 1.
    Tofauti ya saa = 120∘15∘/saa=8\frac{120^\circ}{15^\circ/\text{saa}} = 8 saa.

  4. Kokotoa saa katika mji A.

    Kwa kuwa mji A uko Magharibi mwa mji E, saa itakuwa nyuma.
    Saa katika E = 3:00 P.M. (au 15:00).
    Saa katika A = 15:00 - 8 saa = 7:00.
    Kwa hiyo, saa katika mji A itakuwa 7:00 A.M.

    Jibu:
    Saa katika mji ulioko kwenye mstari A itakuwa:

    7:00 A.M.\boxed{\text{}7:00 \text{ A.M.}}

Part b(v)

41∘F\text{}41^\circ \text{F}

Tuseme joto katika mji ulioko kwenye mstari A ni 5∘C5^\circ \text{C}. Eleza joto hilo katika nyuzi joto za Fahrenheits (∘F^\circ \text{F}).

  1. Tumia fomula ya kubadilisha Celsius kwenda Fahrenheit.

    Fomula ni: TF=TC×95+32T_F = T_C \times \frac{9}{5} + 32.
    Ambapo TFT_F ni joto katika Fahrenheit na TCT_C ni joto katika Celsius.

  2. Badilisha thamani ya joto la Celsius kwenye fomula.

    TC=5∘CT_C = 5^\circ \text{C}.

    TF=5×95+32T_F = 5 \times \frac{9}{5} + 32

  3. Kokotoa thamani ya Fahrenheit.

    TF=9+32T_F = 9 + 32 TF=41∘FT_F = 41^\circ \text{F}

    Jibu:
    Joto katika Fahrenheit ni:

    41∘F\boxed{\text{}41^\circ \text{F}}
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