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What is the distance between Cape Town and Hondeklipbaai in metres?

Geography

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3.2.3 What is the distance between Cape Town and Hondeklipbaai in metres?

  1. Identify the distances between the main towns on the strip chart.

    • Cape Town to Malmesbury: 60 km60 \text{ km}
    • Malmesbury to Piketberg: 50 km50 \text{ km}
    • Piketberg to Clanwilliam: 60 km60 \text{ km}
    • Clanwilliam to Citrusdal: 30 km30 \text{ km}
    • Citrusdal to Vanrhynsdorp: 80 km80 \text{ km}
    • Vanrhynsdorp to Garies: 120 km120 \text{ km}
    • Garies to Kamieskroon: 60 km60 \text{ km}
  2. Calculate the total distance from Cape Town to Garies.

    Distance (CT to Garies)=60 km+50 km+60 km+30 km+80 km+120 km=400 km\text{Distance (CT to Garies)} = 60 \text{ km} + 50 \text{ km} + 60 \text{ km} + 30 \text{ km} + 80 \text{ km} + 120 \text{ km} = 400 \text{ km}
  3. Determine the distance from Garies to the Hondeklipbaai turn-off.

    The note states: "The bypass to Hondeklipbaai is in the middle of Garies and Kamieskroon."
    The distance between Garies and Kamieskroon is 60 km60 \text{ km}.
    So, the turn-off is halfway:

    Distance (Garies to turn-off)=60 km2=30 km\text{Distance (Garies to turn-off)} = \frac{60 \text{ km}}{2} = 30 \text{ km}
  4. Calculate the total distance from Cape Town to the Hondeklipbaai turn-off.

    Total distance (CT to turn-off)=Distance (CT to Garies)+Distance (Garies to turn-off)\text{Total distance (CT to turn-off)} = \text{Distance (CT to Garies)} + \text{Distance (Garies to turn-off)} Total distance (CT to turn-off)=400 km+30 km=430 km\text{Total distance (CT to turn-off)} = 400 \text{ km} + 30 \text{ km} = 430 \text{ km}
  5. Convert the total distance from kilometers to meters.

    1 km=1000 m1 \text{ km} = 1000 \text{ m} Total distance in m=430 km×1000 m/km=430000 m\text{Total distance in m} = 430 \text{ km} \times 1000 \text{ m/km} = 430000 \text{ m}

    The actual distance between Cape Town and Hondeklipbaai is 430000 m\boxed{\text{430000 m}}.

    3.2.4 Koketso travelled from Malmesbury to Springbok. Prove if he was within the accepted speed limit if it took him 4 hours and 30 minutes to reach his destination.

  6. Calculate the total distance from Malmesbury to Springbok using the strip map.

    • Malmesbury to Piketberg: 50 km50 \text{ km}
    • Piketberg to Clanwilliam: 60 km60 \text{ km}
    • Clanwilliam to Citrusdal: 30 km30 \text{ km}
    • Citrusdal to Vanrhynsdorp: 80 km80 \text{ km}
    • Vanrhynsdorp to Garies: 120 km120 \text{ km}
    • Garies to Kamieskroon: 60 km60 \text{ km}
    • Kamieskroon to Springbok: 70 km70 \text{ km}
    Total distance=50+60+30+80+120+60+70=480 km\text{Total distance} = 50 + 60 + 30 + 80 + 120 + 60 + 70 = 480 \text{ km}
  7. Convert the travel time to hours.

    Time taken =4 hours and 30 minutes= 4 \text{ hours and } 30 \text{ minutes}

    30 minutes=3060 hours=0.5 hours30 \text{ minutes} = \frac{30}{60} \text{ hours} = 0.5 \text{ hours} Total time=4 hours+0.5 hours=4.5 hours\text{Total time} = 4 \text{ hours} + 0.5 \text{ hours} = 4.5 \text{ hours}
  8. Calculate Koketso's average speed.

    Speed=DistanceTime\text{Speed} = \frac{\text{Distance}}{\text{Time}} Speed=480 km4.5 hours≈106.67 km/hr\text{Speed} = \frac{480 \text{ km}}{4.5 \text{ hours}} \approx 106.67 \text{ km/hr}
  9. Compare the calculated speed with the accepted speed limit.

    Accepted speed limit =120 km/hr= 120 \text{ km/hr}
    Koketso's speed ≈106.67 km/hr\approx 106.67 \text{ km/hr}
    Since 106.67 km/hr<120 km/hr106.67 \text{ km/hr} < 120 \text{ km/hr}, Koketso was within the accepted speed limit.
    Koketso was within the accepted speed limit.\boxed{\text{Koketso was within the accepted speed limit.}}

    3.2.5 Calculate the probability (to two decimal places) of choosing an even-numbered road from the regional roads.

  10. Identify all numbered regional roads from the strip map.

    The regional roads are those branching off the main N7 National Road:

    • R303 (to Ceres)
    • R27 (to Calvinia)
    • R364 (to Lamberts Bay)
    • R45 (to Vredenburg)
    • R307 (to Darling)
    • R311 (to Moorreesburg) Total number of regional roads =6= 6.
  11. Identify the even-numbered regional roads.

    • R303 (odd)
    • R27 (odd)
    • R364 (even)
    • R45 (odd)
    • R307 (odd)
    • R311 (odd) Number of even-numbered regional roads =1= 1 (R364).
  12. Calculate the probability.

    Probability=Number of even-numbered regional roadsTotal number of regional roads\text{Probability} = \frac{\text{Number of even-numbered regional roads}}{\text{Total number of regional roads}} Probability=16\text{Probability} = \frac{1}{6}
  13. Convert the probability to two decimal places.

    Probability≈0.1666...≈0.17\text{Probability} \approx 0.1666... \approx 0.17

    The probability of choosing an even-numbered road from the regional roads is 0.17\boxed{\text{0.17}}.

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