State what the following initials stand for as used in survey: i) IS: ii) CP: iii) TBM: iv) VI:

Fresh day 😘ð💞ø💘m💋m💘ą💝řř💗í, let's solve. Question (g): State what the following initials stand for as used in survey i) IS: Intermediate Sight ii) CP: Change Point iii) TBM: Temporary Bench Mark iv) VI: Vertical Interval Question Two (15 Marks) a) The above figure represents Mrs Chebukatis piece of land in Bukura Kabati village. She has approached you as an expert to assist her determine her land area in: The figure shows a baseline divided into 6 equal intervals of 9 m each, making the total baseline length 6 × 9 = 54 m. There are 7 offsets given: O_1=7, O_2=12, O_3=15, O_4=20, O_5=12, O_6=13, O_7=9. We will use Simpson's Rule to calculate the area. The common interval W = 9 m. The formula for Simpson's Rule is: A = (W)/(3) [ (O_1 + O_n) + 4(sum of even offsets) + 2(sum of remaining odd offsets) ] Step 1: Identify the offsets and common interval. W = 9 m O_1 = 7 m O_2 = 12 m O_3 = 15 m O_4 = 20 m O_5 = 12 m O_6 = 13 m O_7 = 9 m Step 2: Calculate the sum of the first and last offsets. O_1 + O_7 = 7 + 9 = 16 m Step 3: Calculate the sum of the even offsets. O_2 + O_4 + O_6 = 12 + 20 + 13 = 45 m Step 4: Calculate the sum of the remaining odd offsets (excluding the first and last). O_3 + O_5 = 15 + 12 = 27 m Step 5: Apply Simpson's Rule to find the area in M^2. A = (9)/(3) [ (16) + 4(45) + 2(27) ] A = 3 [ 16 + 180 + 54 ] A = 3 [ 250 ] A = 750 m^2 i) Area in M^2: 750 m^2 Step 6: Convert the area to Acres. Given that 1 acre = 4046.86 m^2. Area in Acres = 750 m^24046.86 m^2/acre Area in Acres ≈ 0.1853 acres ii) Area in Acres: 0.1853 acres Step 7: Convert the area to Hectares. Given that 1 hectare = 10000 m^2. Area in Hectares = 750 m^210000 m^2/hectare Area in Hectares = 0.075 hectares iii) Area in Hectares: 0.075 hectares b) Below is the data collected during chain survey carried out at Bukura Agricultural College main farm by survey students Area they calculated was 4.5 acres Distance they recorded using a chain length of 29.5m was 340m If the length of their standard chain was 30m, calculate; i) The correct distance in Meters Step 1: Use the formula for correct distance. Correct Distance = Recorded Distance × Faulty Chain LengthStandard Chain Length Step 2: Substitute the given values. Correct Distance = 340 m × 29.5 m30 m Correct Distance = 340 × 0.98333... Correct Distance ≈ 334.33 m The correct distance in Meters is 334.33 m. ii) The correct area in Hectares Step 1: Use the formula for correct area. Correct Area = Calculated Area × ( Faulty Chain LengthStandard Chain Length )^2 Step 2: Substitute the given values. Correct Area = 4.5 acres × ( 29.5 m30 m )^2 Correct Area = 4.5 × (0.98333...)^2 Correct Area = 4.5 × 0.966944... Correct Area ≈ 4.35125 acres Step 3: Convert the correct area from acres to hectares. Given that 1 acre = 0.404686 hectares. Correct Area in Hectares = 4.35125 acres × 0.404686 hectaresacre Correct Area in Hectares ≈ 1.7616 hectares The correct area in Hectares is 1.76 hectares. Question Three (a): The question is incomplete as the table of data for the levelling exercise is cut off. Please provide the full table and the specific questions related to it for me to solve. Send me the next one 📸