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For the conjugate of the complex number c = 2 − i.

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27

3\text{3}

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Question 27:
The question asks for the conjugate of the complex number c=2−ic = 2 - i.
The conjugate of a complex number a−bia - bi is a+bia + bi.
Therefore, the conjugate of 2−i2 - i is 2+i2 + i.

The correct option is 3.

3\boxed{\text{3}}

Question 28:
The question asks for the solution set of the equation c2+7c−12=0c^2 + 7c - 12 = 0.
We use the quadratic formula c=−b±b2−4ac2ac = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.
Here, a=1a=1, b=7b=7, $c

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