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850 m/s\text{850 m/s}

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Part 4

Part b

850 m/s\text{850 m/s}

To determine the speed of sound in air, we need to find the time it takes for the sound to travel from the speaker to the microphone and the distance between them.

  1. Determine the time difference (Δt\Delta t) between the two waves from the oscilloscope display.

    The oscilloscope shows two waves. Channel 1 (speaker) represents the sound emitted, and Channel 2 (microphone) represents the sound received.
    The time base is given as 0.5 ms/div.
    By observing the graph, the peak of the wave from Channel 1 aligns with a major grid line. The corresponding peak for Channel 2 is 2 divisions to the right of the Channel 1 peak.
    So, the time difference is:

    Δt=2 divisions×0.5 ms/division\Delta t = 2 \text{ divisions} \times 0.5 \text{ ms/division} Δt=1.0 ms\Delta t = 1.0 \text{ ms}
  2. Convert the time difference to seconds.

    Δt=1.0×10−3 s\Delta t = 1.0 \times 10^{-3} \text{ s}
  3. Use the distance between the speaker and the microphone and the calculated time difference to find the speed of sound (vv).

    The distance dd is given as 0.85 m.
    The formula for speed is:

    v=dΔtv = \frac{d}{\Delta t}
  4. Substitute the values and calculate the speed.

    v=0.85 m1.0×10−3 sv = \frac{0.85 \text{ m}}{1.0 \times 10^{-3} \text{ s}} v=850 m/sv = 850 \text{ m/s}

    The speed of sound in air is 850 m/s\boxed{\text{850 m/s}}.

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