This geography problem is solved step by step below, with detailed explanations to help you understand the method and arrive at the correct answer.

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Answer
A \times v$$
1.14 Velocity in the meandering channel
In a meandering river channel, velocity is lowest at the inner (concave) bank due to higher friction and deposition, and highest at the outer (convex) bank due to superelevation and less friction.
From the diagram, the flow velocity (m/s) indicators show:
Highest velocity at the outer bend (point B or corresponding label).
1.15 Discharge in the river
Discharge (volume flow rate) is given by the formula:
where:
Units: m³/s.
depends on both cross-sectional area and average velocity at the point.
From diagram options: (a) (or corresponding):
1.16 Mouth of the river on the longitudinal profile
The longitudinal profile shows elevation decreasing from source (left, high) to ocean (right, low).
P is near the source (steep gradient).
The mouth (where river meets sea) is at the ocean end.
A ved havet
1.17 (Assuming standard follow-up: Where is gradient steepest?)
Gradient (slope) is steepest near source.
D ved P (or corresponding point near source).
1.18 (Assuming: Where is discharge greatest?)
Discharge increases downstream as tributaries add water.
Greatest at mouth/ocean.
A ved havet
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1.14 Velocity in the meandering channel In a meandering river channel, velocity is lowest at the inner (concave) bank due to higher friction and deposition, and highest at the outer (convex) bank due to superelevation and less friction.
This geography problem is solved step by step below, with detailed explanations to help you understand the method and arrive at the correct answer.