1+2+3+……+49+50+49+48+….+3+2+1) fdlds cjkcj gS&

Step 1: The sum is $1 + 2 + \dots + 49 + 50 + 49 + \dots + 3 + 2 + 1$.
This equals the sum from 1 to 50 plus the sum from 1 to 49:
$\sum_{k=1}^{50} k + \sum_{k=1}^{49} k$

Step 2: Use the formula for the sum of the first $n$ natural numbers:
$\sum_{k=1}^{n} k = \frac{n(n+1)}{2}$

Step 3: Compute $\sum_{k=1}^{50} k$:
$\frac{50 \times 51}{2} = \frac{2550}{2} = 1275$

Step 4: Compute $\sum_{k=1}^{49} k$:
$\frac{49 \times 50}{2} = \frac{2450}{2} = 1225$

Step 5: Add the results:
$1275 + 1225 = 2500$

2500