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1 Write down all the possible factors for each of the following expressions. 1.2 Determine the H.C.F. of the algebraic expression 3a2b + 4ab2.

Mathematics

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2 parts
1.1

1,3,a,a2,b,ab,a2b,3a,3a2,3b,3ab,3a2b1, 3, a, a^2, b, ab, a^2b, 3a, 3a^2, 3b, 3ab, 3a^2b

1,2,4,a,b,b2,ab,ab2,2a,2b,2b2,2ab,2ab2,4a,4b,4b2,4ab,4ab21, 2, 4, a, b, b^2, ab, ab^2, 2a, 2b, 2b^2, 2ab, 2ab^2, 4a, 4b, 4b^2, 4ab, 4ab^2

1.2

ab

Step-by-step solution

3 steps

here are the solutions to the factorization problems:

Part 1.1

Write down all the possible factors for each of the following expressions.

  • For 3a2b3a^2b: The factors are the combinations of the numerical factors of 3 (1,31, 3) and the variable factors of a2ba^2b (1,a,a2,b,ab,a2b1, a, a^2, b, ab, a^2b). Factors: 1,3,a,a2,b,ab,a2b,3a,3a2,3b,3ab,3a2b\boxed{1, 3, a, a^2, b, ab, a^2b, 3a, 3a^2, 3b, 3ab, 3a^2b}

  • For 4ab24ab^2: The factors are the combinations of the numerical factors of 4 (1,2,41, 2, 4) and the variable factors of ab2ab^2 (1,a,b,b2,ab,ab21, a, b, b^2, ab, ab^2). Factors: 1,2,4,a,b,b2,ab,ab2,2a,2b,2b2,2ab,2ab2,4a,4b,4b2,4ab,4ab2\boxed{1, 2, 4, a, b, b^2, ab, ab^2, 2a, 2b, 2b^2, 2ab, 2ab^2, 4a, 4b, 4b^2, 4ab, 4ab^2}

Part 1.2ab

Determine the H.C.F. of the algebraic expression.

The algebraic expression is 3a2b+4ab23a^2b + 4ab^2. We need to find the H.C.F. of the terms 3a2b3a^2b and 4ab24ab^2.

  1. Find the H.C.F.

    of the numerical coefficients.
    The coefficients are 3 and 4.
    Factors of 3: $1, 3$
    Factors of 4: $1, 2, 4$
    The highest common factor of 3 and 4 is 1.

  2. Find the H.C.F.

    of the variable parts.
    For the variable aa: The terms have a2a^2 and aa. The lowest power is aa.
    For the variable bb: The terms have bb and b2b^2. The lowest power is bb.

  3. Multiply the common factors.

    H.C.F. =1×a×b=ab= 1 \times a \times b = \boxed{ab}

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