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Find the H.C.F. of the algebraic expression 3a2b + 4ab2 and express it in factored form.

Mathematics

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Answer

a

2, 2, a, b, b\text{2, 2, a, b, b}

Step-by-step solution

3 steps
  1. Identify the factors for each term in the expression 3a2b+4ab23a^2b + 4ab^2.

    The two terms are 3a2b3a^2b and 4ab24ab^2.
    For the term 3a2b3a^2b:

    3a2b=3×a×a×b3a^2b = 3 \times a \times a \times b

    The individual factors are 3, aa, aa, bb.

    For the term 4ab24ab^2:

    4ab2=2×2×a×b×b4ab^2 = 2 \times 2 \times a \times b \times b

    The individual factors are 2, 2, aa, bb, bb.

  2. Determine the H.C.F.

    (Highest Common Factor) of the algebraic expression 3a2b+4ab23a^2b + 4ab^2.
    To find the H.C.F., we look for common factors in both terms.
    Factors of 3a2b3a^2b: 3,a,a,b3, a, a, b
    Factors of 4ab24ab^2: 2,2,a,b,b2, 2, a, b, b

    The common factors are aa and bb.
    The numerical coefficients are 3 and 4. Their H.C.F. is 1.
    Therefore, the H.C.F. of 3a2b3a^2b and 4ab24ab^2 is a×b=aba \times b = ab.

  3. Write the expression 3a2b+4ab23a^2b + 4ab^2 as an equivalent algebraic expression by factoring out the H.C.F.

    The H.C.F. found in Step 2 is abab.
    Factor abab from each term:

    3a2b+4ab2=ab(3a2bab+4ab2ab)3a^2b + 4ab^2 = ab \left( \frac{3a^2b}{ab} + \frac{4ab^2}{ab} \right) 3a2b+4ab2=ab(3a+4b)3a^2b + 4ab^2 = ab(3a + 4b)

    a) The possible factors for 3a2b3a^2b are: 3, a, a, b\boxed{\text{3, a, a, b}}
    The possible factors for 4ab24ab^2 are: 2, 2, a, b, b\boxed{\text{2, 2, a, b, b}}

    b) The H.C.F. of the algebraic expression is: ab\boxed{ab}

    c) The equivalent algebraic expression is: ab(3a+4b)\boxed{ab(3a + 4b)}

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