1200000 ka 3rupya ka sekra se kitna hota hai 1manth ka

Mathematics

ScanSolve AI Answer

Answer

36000 rupees36000\ \text{rupees}

Step-by-step solution

2 steps

  1. Identify the given values.

    The principal amount (P) is 1,200,000.
    The interest rate (R) is 3 rupees per hundred, which means 3% per month.
    The time period (T) is 1 month.

  2. Calculate the simple interest.

    The formula for simple interest is:

    Simple Interest (SI)=P×R×T100\text{Simple Interest (SI)} = \frac{P \times R \times T}{100}

    Substitute the given values into the formula:

    SI=1,200,000×3×1100\text{SI} = \frac{1,200,000 \times 3 \times 1}{100} SI=3,600,000100\text{SI} = \frac{3,600,000}{100} SI=36,000\text{SI} = 36,000

    The interest for 1 month is 36,000 rupees.

    The interest for 1 month is 36000\ rupees.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question

More Mathematics Questions

Q101+102+103..........200 ka maan kya hogaQRoot ka value kitna hota haiQDate of birth 31.3.200 to abhi kitna sal kitna mahina kitna din hua
See all Mathematics questions →
Got a syllabus? Photograph it and I'll tell you what's due and what's worth the most.