101+102+103..........200 ka maan kya hoga

Step 1: Identify the series. This is an arithmetic progression with the first term $a_1 = 101$, the last term $a_n = 200$, and a common difference $d = 1$.

Step 2: Find the number of terms ($n$). The formula for the $n$-th term of an arithmetic progression is $a_n = a_1 + (n-1)d$. Substitute the known values: $200 = 101 + (n-1) \times 1$. $200 - 101 = n - 1$. $99 = n - 1$. $n = 99 + 1 = 100$. There are 100 terms in the series.

Step 3: Calculate the sum of the arithmetic progression. The formula for the sum of an arithmetic progression is $S_n = \frac{n}{2}(a_1 + a_n)$. Substitute the values: $S_{100} = \frac{100}{2}(101 + 200)$. $S_{100} = 50(301)$. $S_{100} = 15050$.

$101+102+103+\dots+200 = 15050$

The sum of the series is 15050.