(13) 2 1/5 / 7 = and (14) 49 9/6 =

Question

ScanSolve AI Tutor · Accepted Answer

Here are the solutions to the problems:

Part 2: Change each of these mixed numbers with improper fractions to whole or mixed numbers. Reduce your answers to lowest terms if necessary.

For (13) $2\frac{15}{7}$ :

Convert the improper fraction part $\frac{15}{7}$ to a mixed number.
$\frac{15}{7} = 2\frac{1}{7}$
Add this to the whole number part of the original mixed number.
$2 + 2\frac{1}{7} = 4\frac{1}{7}$
The fraction is already in lowest terms.
(13) $\boxed{4\frac{1}{7}}$

For (14) $49\frac{9}{6}$ :
Convert the improper fraction part $\frac{9}{6}$ to a mixed number.
$\frac{9}{6} = 1\frac{3}{6}$
Reduce the fractional part $\frac{3}{6}$ to lowest terms by dividing the numerator and denominator by their greatest common divisor, which is 3.
$1\frac{3}{6} = 1\frac{3 \div 3}{6 \div 3} = 1\frac{1}{2}$
Add this to the whole number part of the original mixed number.
$49 + 1\frac{1}{2} = 50\frac{1}{2}$
(14) $\boxed{50\frac{1}{2}}$

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