16th term of the arithmetic sequence 5,12,19,26, ... ... ... is

Here are the solutions to the problems:

1. 16th term of the arithmetic sequence 5,12,19,26, ... ... ... is

Step 1: Identify the first term ($a$) and the common difference ($d$).
The first term is $a = 5$.
The common difference is $d = 12 - 5 = 7$.

Step 2: Use the formula for the $n^{th}$ term of an arithmetic sequence, $a_n = a + (n-1)d$.
For the 16th term ($n=16$):

$$a_{16} = 5 + (16-1) \times 7$$ $$$$