Find A (2,4) B(3,6) find magntids AB find gradient AB

Mathematics

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Answers

2 parts
1

5\sqrt{5}

2
2

Step-by-step solution

5 steps

Part 1· 3 steps

Find magnitude AB

  1. Identify coordinates

    Let point A be (x1,y1)=(2,4)(x_1, y_1) = (2, 4) and point B be (x2,y2)=(3,6)(x_2, y_2) = (3, 6).

  2. Calculate the change in x and y

    Δx=x2−x1=3−2=1\Delta x = x_2 - x_1 = 3 - 2 = 1
    Δy=y2−y1=6−4=2\Delta y = y_2 - y_1 = 6 - 4 = 2

  3. Calculate the magnitude (distance)

    The magnitude of AB is given by the distance formula:
    Magnitude AB=(Δx)2+(Δy)2\text{Magnitude AB} = \sqrt{(\Delta x)^2 + (\Delta y)^2}
    Magnitude AB=(1)2+(2)2\text{Magnitude AB} = \sqrt{(1)^2 + (2)^2}
    Magnitude AB=1+4\text{Magnitude AB} = \sqrt{1 + 4}
    Magnitude AB=5\text{Magnitude AB} = \sqrt{5}

    The magnitude of AB is 5\boxed{\sqrt{5}}.


Part 22

Find gradient AB

  1. Identify coordinates

    Let point A be (x1,y1)=(2,4)(x_1, y_1) = (2, 4) and point B be (x2,y2)=(3,6)(x_2, y_2) = (3, 6).

  2. Calculate the gradient (slope)

    The gradient of the line segment AB is given by the formula:
    Gradient AB=y2−y1x2−x1\text{Gradient AB} = \frac{y_2 - y_1}{x_2 - x_1}
    Gradient AB=6−43−2\text{Gradient AB} = \frac{6 - 4}{3 - 2}
    Gradient AB=21\text{Gradient AB} = \frac{2}{1}
    Gradient AB=2\text{Gradient AB} = 2

    The gradient of AB is 2\boxed{2}.

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