Solve 2(x + 4) ext >= 5x - 1, graph the solution, change 111012 to base ten, and find the time when three machines produce packages simultaneously.

This can also be written as $x \le 3$.

The solution $x \le 3$ means all numbers less than or equal to 3. On a number line, this is represented by a closed circle at 3 and an arrow extending to the left.

<------------------•--------------------->
   -1   0   1   2   3   4   5
              <----- (closed circle at 3, arrow to the left)

The solution is $\boxed{x \le 3}$.

4b. Change $11101_2$ to base ten numeral.

To convert a binary number to base ten, multiply each digit by the corresponding power of 2.

So, $11101_2 = \boxed{29_{10}}$.

5a. Three machines in a factory produce packages. Machine A every 12 minutes, Machine B every 18 minutes, and Machine C every 24 minutes. Find the time (in minutes) when all three machines will produce a package at the same time.

This problem requires finding the Least Common Multiple (LCM) of 12, 18, and 24.

For prime factor 2: The highest power is $2^3$ (from 24).
For prime factor 3: The highest power is $3^2$ (from 18).

All three machines will produce a package at the same time after $\boxed{72 \text{ minutes}}$.

5b. If an item is sold at a 20% profit for GH¢60, find the cost price.

Let the cost price be $C$.
The selling price (SP) is GH¢60.
The profit percentage is 20%.

The selling price is the cost price plus the profit.

So,

To find $C$, divide the selling price by 1.20.

The cost price is $\boxed{\text{GH¢}50}$.

5c. Arrange the numbers $-20, 15, -2, 0, 56, 4$ in ascending order.

Ascending order means arranging numbers from the smallest to the largest.
The given numbers are: $-20, 15, -2, 0, 56, 4$.

$-20$ is smaller than $-2$. So, $-20, -2$.

0 comes after the negative numbers. So, $-20, -2, 0$.

The positive numbers are $15, 56, 4$.
Arranging them: $4, 15, 56$.