Solve the following arithmetic problems: 1. 1000 imes 1000 2. 80 ext extdiv ext 3 3. 16,000 imes 7

$$1000 \times 1000 = 1,000,000$$

The product of 1000 and 1000 is one million.

$$\boxed{1,000,000}$$

$$80 \div 3 = \frac{80}{3}$$

As a decimal, this is a repeating decimal.

$$\frac{80}{3} = 26.666...$$

We can express it as a mixed number or a repeating decimal.

$$\boxed{26 \frac{2}{3} \text{ or } 26.6\overline{6}}$$

Multiply the non-zero digits first.

$$16 \times 7 = 112$$

Then add the three zeros back.

$$16,000 \times 7 = 112,000$$

The product of 16,000 and 7 is one hundred twelve thousand.

$$\boxed{112,000}$$