Solve the following arithmetic problems involving addition: 1. Sum of 36,534; 52,689; 10,214. 2. Sum of 23…

Question

Solve the following arithmetic problems involving addition: 1. Sum of 36,534; 52,689; 10,214. 2. Sum of 23 thousand, 42 hundred, 17 tens. 3. Add by suitable arrangement: 28,305 + 16,838 + 41,695. 4. F

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Here are the solutions to the problems: 1. Find the sum of 36,534; 52,689; 10,214 Step 1: Add the numbers. 36,534 + 52,689 + 10,214 Step 2: Perform the addition. 36,534 + 52,689 = 89,223; 89,223 + 10,214 = 99,437 The sum is 99,437. 2. Find the sum of 23 thousand, 42 hundred and 17 tens Step 1: Convert the word numbers to standard numerical form. 23 thousand = 23 × 1,000 = 23,000; 42 hundred = 42 × 100 = 4,200; 17 tens = 17 × 10 = 170 Step 2: Add the numerical values. 23,000 + 4,200 + 170 Step 3: Perform the addition. 23,000 + 4,200 = 27,200; 27,200 + 170 = 27,370 The sum is 27,370. 3. Add by suitable arrangement: 28,305 + 16,838 + 41,695 Step 1: Group numbers that are easy to add, typically those whose last digits sum to 10. We can group 28,305 and 41,695 because their last digits (5 and 5) sum to 10, making the addition simpler. (28,305 + 41,695) + 16,838 Step 2: Add the grouped numbers. 28,305 + 41,695 = 70,000 Step 3: Add the remaining number. 70,000 + 16,838 = 86,838 The sum is 86,838. 4. Fill ups a) 27,165 + 0 + 8369 = 8369 + 1cm + 1cm; Step 1: Apply the commutative property of addition (a+b=b+a) and the identity property of zero (a+0=a). The left side is 27,165 + 0 + 8369 = 27,165 + 8369. The right side starts with 8369. To make both sides equal, the remaining terms from the left side must be present on the right side. 27,165 + 8369 = 8369 + 27,165 So, the blanks are 27,165 and 0. 27,165 + 0 + 8369 = 8369 + 27,165 + 0; b) 1,52,343 + (35,363 + 68,313) = 1cm + (1,52,343 + 1cm); Step 1: Apply the associative property of addition (a+(b+c) = (a+b)+c) and the commutative property (a+b=b+a). Let a = 1,52,343, b = 35,363, c = 68,313. The left side is a + (b+c). The right side is blank₁ + (a + blank₂). Using the associative property, a + (b+c) = (a+b) + c. So, (1,52,343 + 35,363) + 68,313. Now, we need to match this to blank₁ + (1,52,343 + blank₂). By the commutative property, (a+b)+c = c+(a+b). So, 68,313 + (1,52,343 + 35,363). Therefore, the first blank is 68,313 and the second blank is 35,363. 1,52,343 + (35,363 + 68,313) = 68,313 + (1,52,343 + 35,363)

Solve the following arithmetic problems involving addition: 1. Sum of 36,534; 52,689; 10,214. 2. Sum of 23 thousand, 42 hundred, 17 tens. 3. Add by suitable arrangement: 28,305 + 16,838 + 41,695. 4. F

Step-by-step solution

Part a· 1 step

Apply the commutative property of addition ( $a+b=b+a$ ) and the identity property of zero ( $a+0=a$ ).

Part b· 1 step

Apply the associative property of addition ( $a+(b+c) = (a+b)+c$ ) and the commutative property ( $a+b=b+a$ ).

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More Mathematics Questions

Solve the following arithmetic problems involving addition: 1. Sum of 36,534; 52,689; 10,214. 2. Sum of 23 thousand, 42 hundred, 17 tens. 3. Add by suitable arrangement: 28,305 + 16,838 + 41,695. 4. F

Step-by-step solution

Part a· 1 step

Apply the commutative property of addition (a+b=b+aa+b=b+aa+b=b+a) and the identity property of zero (a+0=aa+0=aa+0=a).

Part b· 1 step

Apply the associative property of addition (a+(b+c)=(a+b)+ca+(b+c) = (a+b)+ca+(b+c)=(a+b)+c) and the commutative property (a+b=b+aa+b=b+aa+b=b+a).

Still stuck on this one?

More Mathematics Questions

Apply the commutative property of addition ( $a+b=b+a$ ) and the identity property of zero ( $a+0=a$ ).

Apply the associative property of addition ( $a+(b+c) = (a+b)+c$ ) and the commutative property ( $a+b=b+a$ ).