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What are 2D shapes and sequences? Provide definitions, examples, and applications.

Mathematics

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2 parts
i

36, 49, 64\text{36, 49, 64}

ii

19, 23, 27\text{19, 23, 27}

5
45

Step-by-step solution

10 steps

Here are the solutions to the questions.

1a)
A 2D shape is a flat figure that has only two dimensions: length and width. It has no depth or thickness.

1b)
Three examples of 2D shapes are:

  • Triangle
  • Square
  • Circle

1c)
Features of 2D shapes include:

  • They are flat.
  • They have length and width (or height).
  • They have no depth or thickness.
  • They can be measured in terms of area and perimeter.

1d)
2D shapes differ from 3D shapes because 2D shapes are flat and have only two dimensions (length and width), while 3D shapes have three dimensions (length, width, and depth/height) and occupy space.

2a)
A sequence is an ordered list of numbers, called terms, that follow a specific pattern or rule.

2b)
Sequences are important in real life because they help us to predict future values, model growth or decay, and understand patterns in various phenomena.

2c)
Areas where sequences can be used include:

  • Finance (e.g., compound interest, loan payments)
  • Population growth modeling
  • Computer algorithms
  • Music patterns

2d)

Part i· 2 steps

4, 9, 16, 25

  1. Identify the pattern.

    The given terms are 22,32,42,522^2, 3^2, 4^2, 5^2. This is a sequence of perfect squares where the nn-th term is Tn=(n+1)2T_n = (n+1)^2.

  2. Calculate the next three terms.

    For n=5n=5: T5=(5+1)2=62=36T_5 = (5+1)^2 = 6^2 = 36
    For n=6n=6: T6=(6+1)2=72=49T_6 = (6+1)^2 = 7^2 = 49
    For n=7n=7: T7=(7+1)2=82=64T_7 = (7+1)^2 = 8^2 = 64
    The next 3 terms are 36, 49, 64\boxed{\text{36, 49, 64}}.

Part ii

19, 23, 27\text{19, 23, 27}

3, 7, 11, 15

  1. Identify the pattern.

    The difference between consecutive terms is constant: 7−3=47-3=4, 11−7=411-7=4, 15−11=415-11=4. This is an arithmetic sequence with a first term a=3a=3 and a common difference d=4d=4. The nn-th term is Tn=a+(n−1)d=3+(n−1)4=3+4n−4=4n−1T_n = a + (n-1)d = 3 + (n-1)4 = 3 + 4n - 4 = 4n - 1.

  2. Calculate the next three terms.

    For n=5n=5: T5=4(5)−1=20−1=19T_5 = 4(5) - 1 = 20 - 1 = 19
    For n=6n=6: T6=4(6)−1=24−1=23T_6 = 4(6) - 1 = 24 - 1 = 23
    For n=7n=7: T7=4(7)−1=28−1=27T_7 = 4(7) - 1 = 28 - 1 = 27
    The next 3 terms are 19, 23, 27\boxed{\text{19, 23, 27}}.

    3a)

  3. Substitute the value of xx into the function.

    Given f(x)=x+2f(x) = x + 2, we need to find f(3)f(3).

    f(3)=3+2f(3) = 3 + 2
  4. Calculate the result.

    f(3)=5f(3) = 5

    The value is 5\boxed{5}.

    3b)

  5. Substitute the value of xx into the function.

    Given f(x)=9xf(x) = 9x, we need to find f(5)f(5).

    f(5)=9×5f(5) = 9 \times 5
  6. Calculate the result.

    f(5)=45f(5) = 45

    The value is 45\boxed{45}.

    3c)

  7. Substitute the value of xx into the function.

    Given f(x)=9−xf(x) = 9 - x, we need to find f(4)f(4).

    f(4)=9−4f(4) = 9 - 4
  8. Calculate the result.

    f(4)=5f(4) = 5

    The value is 5\boxed{5}.

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