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Use logarithms only to evaluate, correct to 4 decimal places:

Mathematics

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3. Use logarithms only to evaluate, correct to 4 decimal places:

(12.78sin⁡33.45∘(9.063)2)1/3\left(\frac{12.78 \sin 33.45^\circ}{(9.063)^2}\right)^{1/3}

Let X=(12.78sin⁡33.45∘(9.063)2)1/3X = \left(\frac{12.78 \sin 33.45^\circ}{(9.063)^2}\right)^{1/3}.
Taking logarithms to base 10:

log⁡X=13(log⁡(12.78)+log⁡(sin⁡33.45∘)−2log⁡(9.063))\log X = \frac{1}{3} \left( \log(12.78) + \log(\sin 33.45^\circ) - 2 \log(9.063) \right)
  1. Find the logarithm of each term.

    Using logarithm tables:

    • log⁡(12.78)=1.1065\log(12.78) = 1.1065
    • sin⁡33.45∘=0.5512\sin 33.45^\circ = 0.5512 log⁡(sin⁡33.45∘)=log⁡(0.5512)=1ˉ.7413\log(\sin 33.45^\circ) = \log(0.5512) = \bar{1}.7413
    • log⁡(9.063)=0.9572\log(9.063) = 0.9572
  2. Substitute the logarithm values into the equation for log⁡X\log X.

    log⁡X=13(1.1065+1ˉ.7413−2×0.9572)\log X = \frac{1}{3} (1.1065 + \bar{1}.7413 - 2 \times 0.9572) log⁡X=13(1.1065+(−1+0.7413)−1.9144)\log X = \frac{1}{3} (1.1065 + (-1 + 0.7413) - 1.9144) log⁡X=13(1.1065−0.2587−1.9144)\log X = \frac{1}{3} (1.1065 - 0.2587 - 1.9144) log⁡X=13(0.8478−1.9144)\log X = \frac{1}{3} (0.8478 - 1.9144) log⁡X=13(−1.0666)\log X = \frac{1}{3} (-1.0666)
  3. Divide by 3.

    log⁡X=−0.355533...\log X = -0.355533...
  4. Convert the negative logarithm to characteristic-mantissa form.

    −0.3555=−1+0.6445-0.3555 = -1 + 0.6445

    So, $\log X = \bar{1}.6

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