3 years ago Mary was 3 times as old as Oloo.In two years time the sum of their ages will be 62 determine their present ages

Let M be Mary's present age.
Let O be Oloo's present age.

• Condition 1: 3 years ago Mary was 3 times as old as Oloo. Mary's age 3 years ago: M - 3 Oloo's age 3 years ago: O - 3 Equation 1: M - 3 = 3(O - 3) M - 3 = 3O - 9 M = 3O - 6

• Condition 2: In two years time the sum of their ages will be 62. Mary's age in 2 years: M + 2 Oloo's age in 2 years: O + 2 Equation 2: (M + 2) + (O + 2) = 62 M + O + 4 = 62 M + O = 58

We have:

1. M = 3O - 6
2. M + O = 58

Substitute Equation 1 into Equation 2:
(3O - 6) + O = 58
4O - 6 = 58
4O = 58 + 6
4O = 64
O = 64 / 4
O = 16

Substitute O = 16 into Equation 2 (or Equation 1):
M + 16 = 58
M = 58 - 16
M = 42

Therefore, Mary's present age is 42 years, and Oloo's present age is 16 years.