Evaluate 4 1/2 ÷ 1 1/3 + 2 1/3 - 3/4

Mathematics
evaluate 4 1/2 ÷ 1 1/3 + 2 1/3 - 3/4

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1. Evaluate 412÷113+213−344\frac{1}{2} \div 1\frac{1}{3} + 2\frac{1}{3} - \frac{3}{4}

Step 1: Convert all mixed numbers to improper fractions. 412=4×2+12=924\frac{1}{2} = \frac{4 \times 2 + 1}{2} = \frac{9}{2} 113=1×3+13=431\frac{1}{3} = \frac{1 \times 3 + 1}{3} = \frac{4}{3} 213=2×3+13=732\frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{7}{3} The expression becomes: 92÷43+73−34\frac{9}{2} \div \frac{4}{3} + \frac{7}{3} - \frac{3}{4}

Step 2: Perform the division. To divide by a fraction, multiply by its reciprocal. 92÷43=92×34=278\frac{9}{2} \div \frac{4}{3} = \frac{9}{2} \times \frac{3}{4} = \frac{27}{8} The expression becomes: 278+73−34\frac{27}{8} + \frac{7}{3} - \frac{3}{4}

Step 3: Find a common denominator for the fractions. The least common multiple of 8, 3, and 4 is 24. 278=27×38×3=8124\frac{27}{8} = \frac{27 \times 3}{8 \times 3} = \frac{81}{24} 73=7×83×8=5624\frac{7}{3} = \frac{7 \times 8}{3 \times 8} = \frac{56}{24} 34=3×64×6=1824\frac{3}{4} = \frac{3 \times 6}{4 \times 6} = \frac{18}{24} The expression becomes: 8124+5624−1824\frac{81}{24} + \frac{56}{24} - \frac{18}{24}

Step 4: Perform the addition and subtraction. 81+56−1824=137−1824=11924\frac{81 + 56 - 18}{24} = \frac{137 - 18}{24} = \frac{119}{24}

Step 5: Convert the improper fraction to a mixed number. 11924=42324\frac{119}{24} = 4 \frac{23}{24} The final answer is 42324\boxed{4\frac{23}{24}}.

2. A shopkeeper bought 12 bags of maize at 185. He sold them at 225. Find his profits.

Step 1: Determine the total cost price (CP). Assuming "bought 12 bags of maize at 185" means the total cost for all 12 bags was 185. Total CP=185\text{Total CP} = 185

Step 2: Determine the total selling price (SP). Assuming "He sold them at 225" means he sold each bag for 225. Total SP=12 bags×225/bag=2700\text{Total SP} = 12 \text{ bags} \times 225/\text{bag} = 2700

Step 3: Calculate the profit. Profit=Total SP−Total CP\text{Profit} = \text{Total SP} - \text{Total CP} Profit=2700−185=2515\text{Profit} = 2700 - 185 = 2515 The final answer is 2515\boxed{2515}.

3. Solve for α\alpha: 3α+7=2α+193\alpha + 7 = 2\alpha + 19

Step 1: Subtract 2α2\alpha from both sides of the equation to collect α\alpha terms on one side. 3α−2α+7=2α−2α+193\alpha - 2\alpha + 7 = 2\alpha - 2\alpha + 19 α+7=19\alpha + 7 = 19

Step 2: Subtract 7 from both sides of the equation to isolate α\alpha. α+7−7=19−7\alpha + 7 - 7 = 19 - 7 α=12\alpha = 12 The final answer is 12\boxed{12}.

4. A car uses 8 litres of petrol to cover 100 km. How many litres will it cover 325 km?

Step 1: Determine the petrol consumption rate per kilometer. Consumption rate=8 litres100 km=0.08 litres/km\text{Consumption rate} = \frac{8 \text{ litres}}{100 \text{ km}} = 0.08 \text{ litres/km}

Step 2: Calculate the total litres needed for 325 km. Litres needed=Consumption rate×Distance\text{Litres needed} = \text{Consumption rate} \times \text{Distance} Litres needed=0.08 litres/km×325 km\text{Litres needed} = 0.08 \text{ litres/km} \times 325 \text{ km} Litres needed=26 litres\text{Litres needed} = 26 \text{ litres} The final answer is 26 litres\boxed{26 \text{ litres}}.

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