Hey T-Bang, good to see you again. Here's how to solve $42 \div 8$ using long division: Step 1: Divide the first part of the dividend (42) by the divisor (8). We need to find how many times 8 goes into 42 without exceeding it. $8 \times 5 = 40$ $8 \times 6 = 48$ (This is too large) So, 8 goes into 42 five times. Write 5 above the 2 in 42. Step 2: Multiply the quotient digit (5) by the divisor (8). $5 \times 8 = 40$. Write 40 below 42. Step 3: Subtract 40 from 42. $42 - 40 = 2$. This is the remainder. $$ \begin{array}{r} 5 \\ 8\overline{)42} \\ -40 \\ \hline 2 \end{array} $$ The quotient is 5 and the remainder is 2. So, $42 \div 8 = 5$ with a remainder of 2. You can also write this as a mixed number: $$ 5 \frac{2}{8} = 5 \frac{1}{4} $$ Or as a decimal: $$ 5.25 $$ The long division answer is: $\boxed{\text{5 remainder 2}}$ Send me the next one 📸