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गुणनखंड करें - 4x² + y² + z² - 4xy - 2yz + 4xz (ii) 4x² + 9y² + 16z² + 12xy - 24yz - 16xz (iii) x² + 4y² + z² + 4xy - 4yz - 2zx (iv) 4x² + 9y² + 4z² - 12xy - 12yz + 8zx 1/4x² + y² + 1/16z² - xy - 1/2yz + 1/4zx

Mathematics

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यहाँ प्रश्न 8 के भाग (v) का गुणनखंड किया गया है:

8. गुणनखंड करें:

v) 14x2+y2+116z2−xy−12yz+14zx\frac{1}{4}x^2 + y^2 + \frac{1}{16}z^2 - xy - \frac{1}{2}yz + \frac{1}{4}zx

  1. यह व्यंजक (A+B+C)2=A2+B2+C2+2AB+2BC+2CA(A+B+C)^2 = A^2+B^2+C^2+2AB+2BC+2CA के रूप में है।

    यहाँ A2=14x2A^2 = \frac{1}{4}x^2, B2=y2B^2 = y^2, C2=116z2C^2 = \frac{1}{16}z^2 है।
    2AB=−xy  ⟹  A=12x,B=−y2AB = -xy \implies A=\frac{1}{2}x, B=-y (या A=−12x,B=yA=-\frac{1}{2}x, B=y)
    2BC=−12yz  ⟹  B=−y,C=14z2BC = -\frac{1}{2}yz \implies B=-y, C=\frac{1}{4}z
    2CA=14zx  ⟹  C=14z,A=12x2CA = \frac{1}{4}zx \implies C=\frac{1}{4}z, A=\frac{1}{2}x
    इसलिए, A=12x,B=−y,C=14zA=\frac{1}{2}x, B=-y, C=\frac{1}{4}z है।

  2. इन मानों को (A+B+C)2(A+B+C)^2 सूत्र में रखें।

    (12x+(−y)+14z)2\left(\frac{1}{2}x + (-y) + \frac{1}{4}z\right)^2
  3. व्यंजक को सरल करें।

    (12x−y+14z)2\boxed{\left(\frac{1}{2}x - y + \frac{1}{4}z\right)^2}
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