5 Find the L.C.m of 3 9 12 6 Find the L.C.M. of 12 24 6 7 Find the Product of Hz by 8 8…

Question

5 Find the L.C.m of 3 9 12 6 Find the L.C.M. of 12 24 6 7 Find the Product of Hz by 8 8 Simplify-2222-(C(411+60) Find the Produc

ScanSolve AI Tutor · Accepted Answer

Here are the solutions to the problems:

: Find the L.C.M of 3, 9, 12

Find the prime factorization of each number.
$3 = 3^{1}$ $9 = 3^{2}$ $12 = 2^{2} \times 3^{1}$
Identify the highest power of each prime factor present in any of the numbers.
The prime factors are 2 and 3.
The highest power of 2 is $2^{2}$ .
The highest power of 3 is $3^{2}$ .
Multiply these highest powers together to find the L.C.M.
$\text{L.C.M.} = 2^{2} \times 3^{2} = 4 \times 9 = 36$
The L.C.M. of 3, 9, and 12 is $\boxed{\text{36}}$ .

: Find the L.C.M. of 12, 24, 6
Find the prime factorization of each number.
$6 = 2^{1} \times 3^{1}$ $12 = 2^{2} \times 3^{1}$ $24 = 2^{3} \times 3^{1}$
Identify the highest power of each prime factor present in any of the numbers.
The prime factors are 2 and 3.
The highest power of 2 is $2^{3}$ .
The highest power of 3 is $3^{1}$ .
Multiply these highest powers together to find the L.C.M.
$\text{L.C.M.} = 2^{3} \times 3^{1} = 8 \times 3 = 24$
The L.C.M. of 12, 24, and 6 is $\boxed{\text{24}}$ .

: Find the Product of 42 by 8
Multiply the two numbers.
$42 \times 8$
Perform the multiplication.
$42 \times 8 = 336$
The product of 42 by 8 is $\boxed{\text{336}}$ .

: Simplify $2222 - (411 + 60)$
Perform the operation inside the parentheses first.
$411 + 60 = 471$
Substitute the sum back into the expression and perform the subtraction.
$2222 - 471 = 1751$
The simplified value is $\boxed{\text{1751}}$ .

5 Find the L.C.m of 3 9 12 6 Find the L.C.M. of 12 24 6 7 Find the Product of Hz by 8 8 Simplify-2222-(C(411+60) Find the Produc